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3 years ago

A 4 kg mass is in free fall. What is the velocity of the mass after 11 seconds

1 answer:

5 0

Velocity of the mass after 11 seconds = ( value of the gravitational acceleration) * ( time )
velocity = ( 9.81 m / s^2 ) ( 11)
velocity = 107.91 meters per second

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When there is no number in front of a chemical formula in a chemical equation, what number is understood?

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3 years ago

Gravitational potential energy is often released by burning substances. true or false

jolli1 [7]

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3 years ago

Read 2 more answers

a wooden block has a mass of 1.2 kg, a specific heat of 710, and is at a temperature of 25*C. what is the block's final temperat

mash [69]

The final temperature of the block is $27.5^{\circ} C$

Explanation:

The amount of thermal energy Q supplied to a substance is related to the increase in temperature of the substance, $\Delta T$ , according to the equation

$Q=mC_s \Delta T$

where:

m is the mass of the substance

$C_s$ is the specific heat capacity of the substance

In this problem, we have:

m = 1.2 kg is the mass of the block

$Q = 2,130 J$ is the amount of energy supplied to the block

$C_s = 710 J/kg^{\circ}C$ is the specific heat capacity of the block

Solving for $\Delta T$ , we find the increase in temperature:

$\Delta T = \frac{Q}{m C_s}=\frac{2130}{(1.2)(710)}=2.5^{\circ}C$

And since the initial temperature was

$T_i = 25^{\circ}C$

The final temperature will be

$T_f = T_i + \Delta T = 25+2.5=27.5^{\circ} C$

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

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3 years ago

A charge of 1.0 × 10-6 μC is located inside a sphere, 1.25 cm from its center. What is the electric flux through the sphere due

Korvikt [17]

Answer:

$\Phi_E=0.11\frac{N\cdot m^2}{C}$

Explanation:

According to Gauss's Law, the electric flux of a charged sphere is the electric field multiplied by the area of the spherical surface:

$\Phi_E=EA\\\Phi_E=E(4\pi R^2)\\\Phi_E=\frac{q}{4\pi \epsilon_0 R^2}(4\pi R^2)\\\Phi_E=\frac{q}{\epsilon_0}$

This is identical to the electric flux of a point charge located in the center of the sphere.

$\Phi_E=\frac{1*10^{-12}C}{8.85*10^{-12} \frac{C^2}{N\cdot m^2}}\\\Phi_E=0.11\frac{N\cdot m^2}{C}$

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leva [86]

If stars never changed, then constellations wouldn't change. But the stars, including the Sun, travel in their own separate orbits through the Milky Way galaxy. The stars move along with fantastic speeds, but they are so far away that it takes a long time for their motion to be visible to us.

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