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Rama09 [41]
2 years ago
14

This graph shows how the concentration of the product of a reaction changed during a chemical reaction. Which sentence best desc

ribes how the concentration of the product changed? 1.0 0.8 0.6 Concentration of junpoid 0.4 0.2 0 20 80 100 40 60 Time A. It increased immediately as the reaction progressed. B. It decreased gradually as the reaction progressed. C. It decreased immediately as the reaction progressed. D. It increased gradually as the reaction progressed.​

Chemistry
2 answers:
sergejj [24]2 years ago
4 0

Answer:the answer is D

Explanation:

AP3X

sashaice [31]2 years ago
4 0

Answer: The Answer is D

Explanation: Because if you look at the graph you can slowly see it increase and also i took the test on A pex...

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Given the following heats of combustion. CH3OH(l) + 3/2 O2(g) CO2(g) + 2 H2O(l) ΔH°rxn = -726.4 kJ C(graphite) + O2(g) CO2(g) ΔH
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The standard enthalpy of formation of methanol is, -238.7 kJ/mole

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The intermediate balanced chemical reaction will be,

C(graphite)+O_2(g)\rightarrow CO_2(g), \Delta H_1=-393.5kJ/mole..[1]

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CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l) , \Delta H_3=-726.4kJ/mole..[3]

Now we will reverse the reaction 3, multiply reaction 2 by 2  then adding all the equations, Using Hess's law:

We get :

C(graphite)+O_2(g)\rightarrow CO_2(g) , \Delta H_1=-393.5kJ/mole..[1]

2H_2(g)+2O_2(g)\rightarrow 2H_2O(l) ,\Delta H_2=2\times (-285.8kJ/mole)=-571.6kJ/mol..[2]

CO_2(g)+2H_2O(l)\rightarrow CH_3OH(g)+\frac{3}{2}O_2(g) ,\Delta H_3=726.4kJ/mole [3]

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+2\times \Delta H_2+\Delta H_3

\Delta H=(-393.5kJ/mole)+(-571.6kJ/mole)+(726.4kJ/mole)

\Delta H=-238.7kJ/mole

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

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