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3 years ago

A 3000 B forcé is applied to car which causes an acceleration of 3m/s^2 what is the mass of the car

Physics

1 answer:

nika2105 [10]3 years ago

8 0

Answer:

1000 Kilograms

Explanation:

Force is equal to mass times acceleration so if the force is 3000 and the acceleration is 3 m/s^2 then all you need to do to find the mass is divide 3000 by 3 which gives you 1000

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A force of 18 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i

dybincka [34]

Answer:

Explanation:

Given

Force=18lb

extension=8in

Using Hooke's law to get the spring constant(k)

F=ke

Then,

K=f/e

K=18/8

K=2.25lb/in

Work done by spring is given by

W=1/2Fe

Or W=1/2ke²

Then,

Work done in stretching the spring to 14in

W=1/2ke²

W=0.5×2.25×14²

W=220.5lbin

1 Inch-pounds Force to Joules = 0.113J

Then, to joules

W=0.133×220.5

W=29.33J

5 0

4 years ago

Decomposition breaks down organic material into simpler units and:

Lady_Fox [76]

Answer:

d.) provides proteins for plants

Explanation:

5 0

3 years ago

A projectile is fired at an upward angle of 35.6° from the top of a 208-m-high cliff with a speed of 170-m/s. What will be its s

sdas [7]

Answer:

Final velocity is 181.61 m/s at angle 40.44° below horizontal.

Explanation:

Initial horizontal velocity = 170 cos 35.6 = 138.23 m/s

Final horizontal velocity = 138.23 m/s

Considering vertical motion of projectile:

Initial vertical velocity, u = 170 sin 35.6 = 98.96 m/s

Acceleration, a = -9.81 m/s²

Displacement, s = -208 m

We have v² = u² + 2as

Substituting

v² = 98.96² + 2 x -9.81 x -208

v = 117.79 m/s

Final velocity,

$v=\sqrt{138.23^2+117.79^2}=181.61m/s$

$\theta =tan^{-1}\left ( \frac{117.79}{138.23}\right )=40.44^0$

Final velocity is 181.61 m/s at angle 40.44° below horizontal.

5 0

4 years ago

Two identical traveling waves, moving in the same direction, are out of phase by π/5.0 rad. What is the amplitude of the resulta

andreev551 [17]

Answer:

Therefore the amplitude of the resultant wave is $=0.95 y_m$

Explanation:

The equation of wave:

y=A sin (kx-ωt)

For wave 1:

y₁=A sin (kx-ωt) = $y_{m}$ sin (kx-ωt)

For wave 2:

y₂=A sin (kx-ωt+Φ) = $y_{m}$ sin (kx-ωt+Φ)

Where A= amplitude= $y_m$

The angular frequency $\omega=\frac{2\pi}{T}$

$k=\frac{2\pi}{\lambda}$ , $\lambda$ = wave length.

t= time

T= Time period

$\phi$ = phase difference = $\frac{\pi}{5}$

The resultant wave will be

y = y₁ + y₂

= $y_m$ sin (kx-ωt) + $y_m$ sin (kx-ωt+Φ)

$=y_m$ {sin (kx-ωt) + sin (kx-ωt+Φ)}

$=y_m\ sin(\frac{kx-\omega t +\phi + kx-\omega t }2)\ cos(\frac{kx-\omega t +\phi -kx+\omega t}2)$

$=y_m\ sin({kx-\omega t +\frac\phi 2)\ cos(\frac{\phi }2)$

$=y_m\ cos(\frac{\phi }2) sin({kx-\omega t +\frac\phi 2)$

Therefore the amplitude of the resultant wave is

$=y_m\ cos(\frac{\phi }2)$

$=y_m\ cos(\frac{\pi }{10})$

$=0.95 y_m$

6 0

4 years ago

describe how you would connect a voltmeter to measure the potential difference across a resistor and an ammeter to measure the c

Vesna [10]

A voltmeter needs to be connected in parallel to the two sites in order to measure the potential difference between them.

<h3>What is a voltmeter?</h3>

The electrical potential difference between two locations in an electric circuit is measured using a voltmeter.
The potential difference between two ends of a current-carrying conductor is measured using a voltmeter.
On a scale that is typically measured in volts, millivolts (0.001 volts), or kilovolts, a voltmeter primarily monitors the voltage of direct or alternating electric current (1,000 volts).
Numerous voltmeters are digital and display readings as numbers.

<h3>How is a voltmeter connected?</h3>

A galvanometer with high resistance is a voltmeter.
Any portion of an electrical circuit can be measured.
Due to its high resistance, it is linked in parallel so that it does not impact the circuit's overall net resistance and does not draw any current by itself.
A device's voltage is measured by a voltmeter connected in parallel, and its current is measured by an ammeter connected in series.

Learn more about voltmeters here

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3 0

2 years ago