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3 years ago

Compare and contrast acids and bases in terms of their h+ ion and oh- ion concentrations.

1 answer:

3 0

Acids mainly have H+ ions in their formulas. When ionized in water, acids yield H+ ions into the water.

Bases mainly have OH- ions in their formulas. When ionized in water, bases yield OH- ions into the water.

Based on this, we can conclude that acids have higher concentrations of H+ while bases have higher concentrations of OH-.

If a solution has equal concentrations of H+ and OH-, then this solution is said to be neutral.

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How many ways can you write butene? Draw them

jek_recluse [69]

Answer: gonna lin k answer key

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3 years ago

Fill in the coefficients that will balance the following reaction: a0NH4Cl + a1Ag3PO4 → a2AgCl + a3(NH4)3PO4

rosijanka [135]

The equation of the reaction before balancing is
a0NH₄Cl + a1Ag₃PO₄ → a2AgCl + a3(NH₄)₃PO₄
PO₄³⁻ ion is balanced.
on the left side, theres 1 (NH₄⁺) ion and right side 3 (NH₄⁺) ions. Therefore if we put the coefficient for NH₄Cl, we will obtain the following equation
3 NH₄Cl + a1Ag₃PO₄ → a2AgCl + a3(NH₄)₃PO₄
3 Ag⁺ ions on the left side and 1 Ag⁺ ion on the right side, so if we put the coefficient of AgCl as 3, following equation obtained
3 NH₄Cl + a1Ag₃PO₄ → 3 AgCl + a3(NH₄)₃PO₄
Cl⁻ ions are also balanced now, 3 on either side.
a1 and a3 are 1 as those compounds are as it is, so coefficient is 1 for both

balanced equation is as follows
3 NH₄Cl + Ag₃PO₄ → 3 AgCl + (NH₄)₃PO₄
coefficients are
a0 - 3
a1 - 1
a2 - 3
a3 - 1

8 0

2 years ago

What word is used synonymously with the word "base"

Inessa [10]

Answer:

foundation/bottom

Explanation:

5 0

3 years ago

What can you say about an atom with 4 protons, 2 neutrons, and 5 electrons?

iren2701 [21]

Explanation:

This is a neutral beryllium atom

5 0

3 years ago

How many grams of nan3 are required to produce 19.0 ft3 of nitrogen gas, about the size of an automotive air bag, if the gas has

Papessa [141]

The balanced chemical reaction is given as:

$2NaN_{3}(s)\rightarrow 2Na(s)+3N_{2}(g)$

Now, convert $19.0 ft^{3}$ into litres.

$1 ft^{3} = 28.3168$

So, $19.0 ft^{3} = 19\times 28.3168 = 538.0192 L$

Density is equal to the ratio of mass to the volume.

$D=\frac{M}{V}$

where, M = mass and V= volume $(538.0192 L)$

Substitute the value of density and volume in formula to get the value of mass.

$1.25 g/L=\frac{M}{538.0192 L}$

$1.25 g/L\times 538.0192 L= M$

$Mass = 672.524 g$

Now, number of moles of $N_{2}$ gas= $\frac{672.524 g}{28.02 g/mol}$

= $24.00 moles$

According to the reaction, 2 moles of sodium azide gives 3 moles of nitrogen gas.

Now, in 24.00 moles of nitrogen gas produced from= $\frac{2 moles of sodium azide}{3 moles of nitrogen gas}\times 24.00 moles$ of nitrogen gas, moles of sodium azide.

number of moles of sodium azide = $16 moles$

Mass of sodium azide in g = $number of moles\times molar mass of sodium azide$ .

= $16 moles\times 65.00 g/mol$

= $1040 g$

Thus, mass of sodium azide which is required to produce $19.0 ft^{3}$ of nitrogen gas = $1040 g$

3 0

3 years ago