<h3><u>Answer and Explanation;</u></h3>
The reaction between Nitrogen and Hydrogen to form ammonia gas is given by the equation;
N₂ + 3H₂ → 2NH₃
From the equation 1 mole of nitrogen gas (28 g) requires 3 moles of hydrogen gas (6 g) to form 2 moles of Ammonia gas (34 g).
Therefore;
Moles of Nitrogen = 14/28 = 0.5 mole
Moles of Ammonia = 16.1 /17 = 0.947 ≈ 1 moles
Therefore;
0.5 mole of nitrogen gas (14 g) requires 1.5 moles of hydrogen gas (3 g) to form 1 mole of Ammonia gas (17 g).
The balanced equation would be;
N₂ + 3H₂ → 2NH₃
Gold, as it has the unique characteristic yo
Answer: A volume of 37.5 mL of 0.300 M NaF would be required to make a 0.0450 M solution of NaF when diluted to 250.0 mL with water.
Explanation:
Given: = 0.300 M, = ?
= 0.0450 M, = 250.0 mL
Formula used is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that a volume of 37.5 mL of 0.300 M NaF would be required to make a 0.0450 M solution of NaF when diluted to 250.0 mL with water.