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lys-0071 [83]
3 years ago
7

Why does the moon turn red during a lunar eclipse?.

Physics
1 answer:
SOVA2 [1]3 years ago
4 0

Answer:

During a lunar eclipse, the Moon turns red because the only sunlight reaching the Moon passes through Earth's atmosphere. The more dust or clouds in Earth's atmosphere during the eclipse, the redder the Moon will appear.

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What is the difference between pulse and periodic waves, and what is the difference between transverse and longitudinal waves?
stiv31 [10]

<u>Difference between pulse and periodic waves:</u>

A pulse wave is a sudden disturbance in which only one wave or a few waves are generated, such as in the example of the pebble. Thunder and explosions also create pulse waves. A periodic wave repeats the same oscillation for several cycles, such as in the case of the wave pool, and is associated with simple harmonic motion. Each particle in the medium experiences simple harmonic motion in periodic waves by moving back and forth periodically through the same positions.

<u>Difference between longitudinal and transverse waves:</u>

A transverse wave propagates when the disturbance is perpendicular to the propagation direction. An example of a transverse wave is where a woman moves a toy spring up and down, generating waves that propagate away from herself in the horizontal direction while disturbing the toy spring in the vertical direction.

In a longitudinal wave, the disturbance is parallel to the propagation direction. Example of longitudinal wave is where the woman now makes a disturbance in the horizontal direction—which is the same direction as the wave propagation—by stretching and then compressing the toy spring.

7 0
4 years ago
An 8 Ω resistor is connected to a battery. The current that flows in the circuit is 2 A. Calculate the voltage of the battery.
Crank

Here is the highly detailed, arcane, complex, technical form of Ohm's Law that is needed in order to answer this question  ===> V = I · R .

Voltage = (current) x (resistance)

Voltage = (2 Ampere) x (8 Ω)

<em>Voltage = 16 volts</em>

7 0
4 years ago
A solar system has the five planets shown below. The mass of each planet is proportion
slava [35]

Answer:

Planet C

Explanation:

The figure of the problem is missing: find it in attachment.

The magnitude of the gravitational force between two objects is given by the equation:

F=\frac{Gm_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

In this problem, we have four planets around planet X, and the mass of each planet is proportional to its size in the figure.

As we can see from the previous equation, the magnitude of the gravitational force is proportional to the mass of the planets: therefore, the planet with largest mass will exert the largest gravitational force on planet X.

From the figure, we see that planet C has the largest size, so the largest mass: therefore, planet C exerts the greatest gravitational force on planet X.

6 0
4 years ago
Suppose that an electron and a positron collide head-on. Both have kinetic energy of 1.20 MeV and rest energy of 0.511 MeV. They
AnnZ [28]

Answer:

E = 1.711 MeV

Explanation:

From the law of the conservation of energy:

K.E_{e}+K.E_p + E_{e}+E_{p} = 2 E

where,

K.E_e=K.Ep= the kinetic energy of positron and electron = 1.2 MeV

E_e=E_p = Rest energy of the electron and the positron = 0.511 MeV

E = Energy of Photon = ?

Therefore,

1.2\ MeV + 1.2\ MeV + 0.511\ MeV + 0.511\ MeV = 2E\\\\E = \frac{3.422\ MeV}{2}\\\\

<u>E = 1.711 MeV</u>

3 0
3 years ago
How much force is needed to slow down a 15 kg car traveling at 60 m/s to 15 m/s in 10 seconds?​
goldfiish [28.3K]

Answer:

The force needed to slow down the car is, F = 67.5 N

Explanation:

Given data,

The mass of the car, m = 15 kg

The initial velocity of the car, V = 60 m/s

The final velocity of the car, v = 15 m/s

The time period of deceleration, t = 10 s

The difference in the momentum of the car is,

                                     mV - mv = 15(60 - 15)

                                                    = 675 kg m/s

The rate of change in momentum of the car gives the force acting on it.

                                    F = (mV - mu) / t

Substituting the values,

                                   F = 675 / 10

                                      = 67.5 N

Hence, the force needed to slow down the car is, F = 67.5 N

3 0
3 years ago
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