Answer:
e) intensity of precipitation f) location of precipitation.
Explanation:
Doppler radar can see not only the precipitation in a thunderstorm (through its ability to reflect microwave energy, or reflectivity), but motion of the precipitation along the radar beam. In other words, it can measure how fast rain or hail is moving toward or away from the radar. From a volume scan (a series of 360-degree sweeps, each tilting a little higher than the last), forecasters can get a detailed look at structures and movements in storms close to the radar. The farther away from the radar a storm is, the more coarse the view, because: 1) The radar beam spreads out with distance, like a flashlight beam, causing small features to be missed at a distance; and 2) The beam shoots straight as the earth curves away from beneath -- a horizon that forces the radar to miss more and more of the low and middle levels of a storm with distance.
https://www.spc.ncep.noaa.gov/faq/tornado/doppler.htm
The explanation was copy pasted from there^ so check it out.
Answer:
0.576M and 0.655m
Explanation:
<em>...Dissolves 15.0g of styrene (C₈H₈) in 250.mL of a solvent with a density of 0.88g/mL...</em>
<em />
Molarity is defined as moles of solute (Styrene in this case) per liter of solution whereas molality is the moles of solute per kg of solvent. Thus, we need to find the moles of styrene, the volume in liters of the solution and the mass in kg of the solvent as follows:
<em>Moles styrene:</em>
Molar mass C₈H₈:
8C = 12.01g/mol*8 = 96.08g/mol
8H = 1.005g/mol* 8 = 8.04g/mol
96.08g/mol + 8.04g/mol = 104.12g/mol
Moles of 15.0g of styrene are:
15.0g * (1mol / 104.12g) = 0.144 moles of styrene
<em>Liters solution:</em>
250mL * (1L / 1000mL) = 0.250L
<em>kg solvent:</em>
250mL * (0.88g/mL) * (1kg / 1000g) = 0.220kg
Molarity is:
0.144 moles / 0.250L =
<h3>0.576M</h3>
Molality is:
0.144 moles / 0.220kg =
<h3>0.655m</h3>
Benefits; helps our red blood cells transport oxygen all around our body
Answer:
smallest unit element are made of
Explanation:
Mass of compounds = Moles of compound × Molecular mass of compound
a) Moles of LiCl = 2.345 mol
Molecular mass of LiCl = 42.5 g/mol
Mass of 2.345 moles of LiCl = 2.345 mol × 42.5 g/mol = 99.6625 g
b) Moles of acetylene = 0.0872 mol
Molecular mass of acetylene= 26 g/mol
Mass of 0.0872 moles acetylene= 0.0872 mol × 26 g/mol = 2.2672 g
c) Moles of sodium carbonate= 
Molecular mass of sodium carbonate= 106 g/mol
Mass of sodium carbonate
= 
= 3.498 g
d) Moles of fructose = 
Molecular mass fructose= 180 g/mol
Mass of fructose
= 
e) Moles of 
Molecular mass of 
Mass of fructose
= 
