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4 years ago

When encountering low visibility from rain or fog, you should use your ____.

Engineering

1 answer:

kirza4 [7]4 years ago

4 0

Answer:

Explanation:

Low beams should only be used when fog and rain is present, as high beams can cause a dangerous glare to you and other drivers. You should also use your fog lights, but not every vehicle has them.

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12. Which of the following letter doesn't still the same when its viewed

Mashcka [7]

Answer:

the correct answer is option B. W

3 0

3 years ago

Read 2 more answers

What are the main differences between structured,<br> O-O, and agile development methods?

fgiga [73]

Answer:While structured analysis sees procedures and information as isolated segments, object-oriented (O-O) analysis joins information and the procedures that follow up on the information into things called objects. O-O analysis utilizes protest models to show information, conduct, and by what implies objects influence different articles. By portraying the items (information) and techniques (forms) expected to help a business task, a framework engineer can outline reusable segments for quicker framework usage and diminished advancement cost.Numerous experts trust that, contrasted and organized examination, O-O strategies are more adaptable, effective, and reasonable in the present unique business environment. Agile improvement techniques have pulled in a wide after and a whole network of clients.

Agile strategies ordinarily utilize a winding model, which speaks to a progression of cycles, or revisions,which depend on client criticism. Advocates of the winding model trust that this approach lessens dangers and accelerates programming advancement. Investigators ought to perceive that lithe techniques have points of interest and hindrances. By their tendency, dexterous strategies enable designers to be considerably more adaptable and responsive, however can be less secure than more customary techniques.For instance, without a point by point set of framework necessities, certain highlights asked for by a few clients won't not be predictable with the organization's bigger course of action. Other potential disservices of versatile strategies can incorporate feeble documentation, obscured lines of responsibility, and too little accentuation on the bigger business picture. Additionally, except if legitimately executed, a long arrangement of emphases may really add to extend cost and advancement time.

4 0

3 years ago

A. A compound gear train is composed of four gears: E,F,G,H. Gear E has 15 teeth and is meshed with gear F. Gear F has 25 teeth

cricket20 [7]

Answer:

What subject is this in?? That would help a lot knowing

Explanation:

5 0

3 years ago

An 80-L vessel contains 4 kg of refrigerant-134a at a pressure of 160kPa. Determine (a) the temperature, (b) the quality, (c) th

makvit [3.9K]

Answer:

temperature -15.6 C, quality x=0.646, enthalpy h=667.20 KJ, volume of vapor phase Vg= 79.8 L

Explanation:

property table for R-134a

https://www.ohio.edu/mechanical/thermo/property_tables/R134a/R134a_PresSat.html

at 160 KPa , temperature = -15.66 C

quality x=mass of vapour/ total mass of liq-vap mixture

alternaternately: x=(v-vf)/(vg-vf)

v=total volume i.e. volume of container"80L" 80L=0.08 cubic meter

vf=vol of liquid phase vg=vol of vapor phase vf, vg values at 160Kpa

x=(0.08-0.0007437)/(0.1235-0.0007437)=0.646

enthalpy

h=hf+xhfg hf, hfg values at 160Kpa

h=hf+xhfg=31.2+0.646(209.9)=166.80 KJ/Kg

for 4Kg R-134a h=m(166.80 KJ/Kg )=667.20 KJ

volume of vapor phase

vg at 160Kpa=0.1235 cubic meter for quality=1.

in this case quality=0.646 , so it will occupy 64.6% space of the vapor phase at quality=1.

vol. of vapor phase=0.646*0.1235=0.0798 cubic meter=79.8 L

7 0

3 years ago

An astronaut weighs 125 lbs on the surface of the Earth. What would she weigh in lbs if she is resting in the space shuttle that

alina1380 [7]

Answer:

weight of astronaut $F_2 = 113.38 lb$

Explanation:

Given data:

astronaut weight is = 125 lbs

distance of shuttle from surface of earth is 200 mils

we know that $F = G \frac{m_1 m_2}{r^2}$

where G, m_1, m_2 are constant value, so we have

$\frac{F_1}{F_2} = \frac{r_2^2}{r_1^2}$

radius of earth is 4000 miles

where r_2 = 4000 + 200 = 4200 miles

$\frac{125}{F_2} = \frac{4200^2}{4000^2}$

$F_2 = 113.38 lb$

3 0

3 years ago