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Kobotan [32]
3 years ago
7

As an object’s speed decreases, its kinetic energy (KE) ________.

Physics
1 answer:
Nikitich [7]3 years ago
7 0
1. Decreases
2. Increases
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15. A body moving with a velocity of 20 m/s begins to accelerate at 3 m/s2. How far does the body move in 5 seconds? A. 137.5 m
Rudik [331]

Answer is B. According to the equation of motion s = vt + 1/2 at2 Where s is distance covered, v is velocity, a is acceleration and t is time taken. So, by putting all the values, we get s = (20)(5) + 1/2 (3)(5)2 s = 100 + 1/2 (3)(25) s = 100 + 1/2 75 s = 100 + 37.5 s = 137.5 meters



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3 years ago
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What is the name of the specification that indicates the frequencies that are dedicated for data transmission over cable lines?
mihalych1998 [28]
The answer to this question is the term
DOCSIS. A DOCSIS or Data Over Cable Service Interface Specification is a telecommunication standard or interface where in an internet was being provided by the use of cables. The advantage of using DOCSIS is that the speed of the internet is faster using this kind of interface.
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The curved section of a horizontal highway is a circular unbanked arc of radius 740 m. If the coefficient of static friction bet
kirill [66]
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4 years ago
In the following lever system, what is the clockwise torque? 18 Nm 240 Nm 360 Nm 480 Nm
MaRussiya [10]

Answer:

240 Nm

Explanation:

The clockwise torque is the torque determined only by the force that makes the lever rotating clockwise: therefore, the force of 80 N on the right.

The torque produced by this force is given by:

\tau = F d

where

F is the magnitude of the force

d is the arm

For the force of 80 N on the right,

F = 80 N

d = 3 m (distance from the pivot)

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3 0
4 years ago
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A 2.10 X 10^3 kg car starts from rest at the top of a 5.0
xeze [42]

Answer:

3.80 m/s

Explanation:

Solution: From the question we have:

A 2.10 x 10^3 kg car starts from rest at the top of a 5.0 m long driveway that is sloped at 20 degrees with the horizontal.

average friction force of 4.0 x 10^3 N impedes the motion

To find out:  find the speed of the car at the bottom of the driveway.

=>h = 5×sin20 = 1.71 m.

PE = mgh = 2100×9.8×1.71 = 35,192 J.

KE = PE-work done by frictional force

KE=PE-4000×5

0.5mV^2 = 35192 - 4000×5

1050V^2 = 15,192

V^2 = 14.47

V = 3.80 m/s.

4 0
3 years ago
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