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pishuonlain [190]
1 year ago
6

Aluminum oxide breaks down into it elemental components when electric current is applied.

Chemistry
1 answer:
Sav [38]1 year ago
8 0

Answer:

The primary use of aluminum oxide is the manufacture of aluminum metal. When an electric current is passed through molten (melted) aluminum oxide, the compound breaks down to form aluminum metal and oxygen gas.

Explanation:

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A decrease in pressure has the greatest effect on a solution that contains.. ?
Naddika [18.5K]
<h3><u>Answer;</u></h3>

A gas in a liquid

<h3><u>Explanation;</u></h3>
  • Pressure affects the solubility of gases. According to Henry's law, the solubility of a gas in a liquid is proportional to the partial pressure of the gas above the liquid at a given temperature,
  • Therefore; For the solubility of gases in liquids, as pressure increases, solubility increases. Hence pressure will have a effect on a solution with a gas in liquid.
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3 years ago
The number of electrons in a neutral atom is equal to the number of protons? True or false
NNADVOKAT [17]

Answer:

true

Explanation:

in order for the atom to be neutral the number of protons and electrons have to be the same.

3 0
2 years ago
The concentrated sulfuric acid we use in the laboratory is 98.0% sulfuric acid by weight. Calculate the molality and molarity of
timama [110]

Answer : The molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

Solution : Given,

Density of solution = 1.83g/cm^3=1.83g/ml

Molar mass of sulfuric acid (solute) = 98.079 g/mole

98.0 % sulfuric acid by mass means that 98.0 gram of sulfuric acid is present in 100 g of solution.

Mass of sulfuric acid (solute) = 98.0 g

Mass of solution = 100 g

Mass of solvent = Mass of solution - Mass of solute = 100 - 98.0 = 2 g

First we have to calculate the volume of solution.

\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}=\frac{100g}{1.83g/ml}=54.64ml

Now we have to calculate the molarity of solution.

Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}=\frac{98.0g\times 1000}{98.079g/mole\times 54.64ml}=18.29mole/L

Now we have to calculate the molality of the solution.

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{98.0g\times 1000}{98.079g/mole\times 2g}=499.59mole/Kg

Therefore, the molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

7 0
3 years ago
What scientific instrument is capable of measuring very small masses?​
marusya05 [52]

Answer:

Electronic balances.

Explanation:

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