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Zolol [24]
3 years ago
14

What is 3,730 watts expressed as horsepwer? A. 10 B. 20 C. 5 D. 30

Physics
1 answer:
Nikitich [7]3 years ago
5 0
<span>just divide it out by how many watts are in a HP
</span><span>5</span>
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Two objects of mass m move in opposite directions toward each other. The green object moves at velocity v, and the blue object m
NeX [460]

. The velocity of a mass attached to a spring is given by v = (1.5 cm/s) sin(ωt + π/2), ..... Which of the following is the motion of objects moving in two dimensions

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3 years ago
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A ball is suspended by a lightweight string, as shown in the figure above.
Irina18 [472]

<u>Answer </u>

A. 1 and 2

<u>Explanation </u>

At point 1 we have the highest potential energy and the kinetic energy is zero.

At 2 the potential energy is minimum and the kinetic energy is maximum.

The law of conservation of energy says that energy cannot be created nor destroyed. So, the change in P.E = Change in K.E.

P.E = height × gravity × mass. The height referred here is the perpendicular height. Gravity and mass are constant in this case.

From the diagram it can be seen clearly that the vertical height from 2 to 1 is much greater than from 4 to 3.

This shows that the change in P.E is greater between 1 and 2 and so is kinetic energy.


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3 years ago
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"The International Space Station (ISS) orbits at a distance of 350 km above the surface of the Earth. (a) Determine the gravitat
vagabundo [1.1K]

Answer:

(a) g = 8.82158145m/s^2.

(b) 7699.990192m/s.

(c)5484.3301s = 1.5234 hours.(extremely fast).

Explanation:

(a) Strength of gravitational field 'g' by definition is

g = \frac{M_{(earth)} }{r^2} G , here G is Gravitational Constant, and r is distance from center of earth, all the values will remain same except r which will be radius of earth + altitude at which ISS is in orbit.

r = 6721,000 meters, putting this value in above equation gives g = 8.82158145m/s^2.

(b) We have to essentially calculate centripetal acceleration that equals new 'g'.

a_{centripetal}=\frac{V^2}{r} =g here g is known, r is known and v is unknown.

plugging in r and g in above and solving for unknown gives V = 7699.990192m/s.

(c)  S = vT,  here T is time period or time required to complete one full revolution.

S =  earth's circumfrence , V is calculated in (B) T is unknown.

solving for unknown gives T = 5484.3301s = 1.5234hours.

3 0
3 years ago
At what angle of projectile range of maximum​
Agata [3.3K]

Answer:

45°

Explanation:

The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees.

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3 years ago
Electrons are added into the outermost what in groups 1 &amp; 2
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S orbital.

Group 1 elements have a general configuration ns^{1}, where n represents the highest occupied Principal Energy Level. For example, Lithium has the valence configuration 2s^{1} whereas Cesium has 6s^{1}. Both of them belong to Group 1 of Periodic Table.

Group 2 elements have a general configuration of ns^{2}. For example, Magnesium has 3s^{2} as its outer shell configuration while Strontium has the same as 5s^{2}.

We see that in both the cases, the outermost S orbital is being filled.

3 0
2 years ago
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