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den301095 [7]
3 years ago
12

Peter left town A at 13:30 and travelled towards town B at an average speed of 40mph. At 13:45 Philip left town A for town B at

an average speed of 30 mph. What was the distance between them at 15:00?
Physics
1 answer:
skad [1K]3 years ago
8 0

Answer:

fbddb

Explanation:

dsbse

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Which is the wavelength of a wave that travels at a speed of 3.0 × 10^8 m/s and has a frequency of 1.5 × 10^16 Hz?
k0ka [10]

Answer:

2 x 10^-8

Explanation:

the formula of wavelength is

the speed divided by frequency

so you have the speed given = 3.0x10^8m/s

and frequency = 1.5×10^16 Hz

so wavelength = 3.0x10^8m/s / 1.5x10^16 Hz

7 0
3 years ago
The voltage in a circuit is given by the equation V = IR . In this equation , Vis the voltage, the current, and Ris the resistan
Mumz [18]

Answer:

The choice D.

R =  \frac{v}{I}

I hope I helped you^_^

8 0
3 years ago
The weight of a metal bracelet is measured to be 0.10400 N in air and 0.08400 N when immersed in water. Find its density.
Anna007 [38]

Answer:

The density of the metal is 5200 kg/m³.

Explanation:

Given that,

Weight in air= 0.10400 N

Weight in water = 0.08400 N

We need to calculate the density of metal

Let \rho_{m} be the density of metal and \rho_{w} be the density of water is 1000kg/m³.

V is volume of solid.

The weight of metal in air is

W =0.10400\ N

mg=0.10400

\rho V g=0.10400

Vg=\dfrac{0.10400}{\rho_{m}}.....(I)

The weight of metal in water is

Using buoyancy force

F_{b}=0.10400-0.08400

F_{b}=0.02\ N

We know that,

F_{b}=\rho_{w} V g....(I)

Put the value of F_{b} in equation (I)

\rho_{w} Vg=0.02

Put the value of Vg in equation (II)

\rho_{w}\times\dfrac{0.10400}{\rho_{m}}=0.02

1000\times\dfrac{0.10400}{0.02}=\rho_{m}

\rho_{m}=5200\ kg/m^3

Hence, The density of the metal is 5200 kg/m³.

6 0
3 years ago
. Một con lắc đơn có chiều dài dây treo 1m dao động điều hoà treo trong một xe chạy trên mặt phẳng nghiêng
lyudmila [28]

Answer:

C

Explanation:

hope for help ....im expert

6 0
3 years ago
Read 2 more answers
An airplane flies 40km directly south in 10 minutes and 20 km directly east in five minutes, its average speed is:
blondinia [14]
Average speed = total distance / total time
total distance = 40 + 20 = 60km
total time taken = 10 + 5 = 15 minutes
Average speed = 60/15 = 4km/min
8 0
3 years ago
Read 2 more answers
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