Peter left town A at 13:30 and travelled towards town B at an average speed of 40mph. At 13:45 Philip left town A for town B at
an average speed of 30 mph. What was the distance between them at 15:00?
1 answer:
Answer:
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Explanation:
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Answer:
-6 m/s²
Explanation:
Given:
v₀ = 50 m/s
v = 20 m/s
t = 5 s
Find: a
v = at + v₀
20 m/s = a (5 s) + 50 m/s
a = -6 m/s²
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Answer:
m/s^-30
Explanation:
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