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3 years ago

Does the equation describe a chemical change or a physical change? Explain your reasoning.

Chemistry

1 answer:

Neporo4naja [7]3 years ago

7 0

Answer:

Chemical change

Explanation:

There are types of changes in nature namely: physical change and chemical change. A physical change is a change that does not alter the chemical composition of the substances involved, hence, no new substances are formed. On the other hand, a chemical change changes the chemical composition of the involved substances to form new substances.

Based on the definition of the types of changes below, the equation depicted in this question is a CHEMICAL CHANGE because it involves a rearrangement of the atoms of each element in the reactants to produce new sets of products with a new chemical formula.

C17H17ON3(s) + 2C4H6O3(l) → C21H21O5N(s) + 2C2H4O2(l)

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The model below shows an atom of an element. 10 light gray and 8 dark gray balls sit at the center with 2 concentric black rings

MA_775_DIABLO [31]

Answer:

The Atomic Number of the atom of an element whose model is given is "8" that is option no. 'C' in the question.

Explanation:

An Atom comprises of 3 basic structures that are Protons, Neutrons and Electrons. The central part is the Nucleus which contains protons and neutrons having positive charge and no charge respectively. The electrons are revolving around the nucleus in electronic shells having the negative charge.

ATOMIC NUMBER:

Atomic number is the number of protons present inside the nucleus of an atom and it determines the place of that particular atom in the Periodic Table.

In the model, given in the question, the nucleus contains 2 types of balls dark gray colored and light gray colored. The key at the bottom shows the dark gray colored ball as having a positive charge and thus it represents the atomic number for the given atom of element which is EIGHT (8).

So, the atomic number for the given atom is 8 which is element OXYGEN.

9 0

3 years ago

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Which of the following is NOT the property of a non-metal? A. Non-rigid structure B. Not ductile C. Low density D. Malleable

Vedmedyk [2.9K]

Answer:

The answer is D.

Explanation:

Malleable is the property of metal not non-metal.

4 0

4 years ago

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How is modeling useful to scientist

Keith_Richards [23]

In science, a model is a representation of an idea, an object or even a process or a system that is used to describe and explain phenomena that cannot be experienced directly. Models are central to what scientists do, both in their research as well as when communicating their explanations.
Models have a variety of uses – from providing a way of explaining complex data to presenting as a hypothesis. There may be more than one model proposed by scientists to explain or predict what might happen in particular circumstances. Often scientists will argue about the ‘rightness’ of their model, and in the process, the model will evolve or be rejected. Consequently, models are central to the process of knowledge-building in science and demonstrate how science knowledge is tentative.

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3 years ago

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An atom has a diameter of 2.50 Å and the nucleus of that atom has a diameter of 9.00×10−5 Å . Determine the fraction of the volu

chubhunter [2.5K]

Answer:

The fraction of the volume of the atom that is taken up by the nucleus is $4.6656\times 10^{-14}$ .

The density of a proton is $6.278\times 10^{14} g/cm^3$ .

Explanation:

Diameter of the atom ,d = 2.50 Å

Radius of the atom ,r = 0.5 d=0.5 × 2.50 Å = 1.25Å

Volume of the sphere= $\frac{4}{3}\pi r^3$

Volume of atom = V

$V=\frac{4}{3}\pi r^3$ ..[1]

Diameter of the nucleus ,d' = $9.00\times 10^{-5}\AA$

Radius of the nucleus ,r' = 0.5 d'= $0.5\times 9.00\times 10^{-5}\AA=4.5\times 10^{-5}\AA$

Volume of nucleus = V'

$V=\frac{4}{3}\pi r'^3$ ..[2]

Dividing [2] by [1]

$\frac{V'}{V}=\frac{\frac{4}{3}\pi r'^3}{\frac{4}{3}\pi r^3}$

$=\frac{r'^3}{r^3}=\frac{(4.5\times 10^{-5}\AA)^3}{(1.25 \AA)^3}$

$\frac{V'}{V}=4.6656\times 10^{-14}$

The fraction of the volume of the atom that is taken up by the nucleus is $4.6656\times 10^{-14}$ .

Diameter of the proton ,d = $1.72\times 10^{-15} m = 1.72\times 10^{-13} cm$

1 m = 100 cm

Radius of the proton,r = 0.5 d= $0.5\times 1.72\times 10^{-13} cm=8.6\times 10^{-14} cm$

Volume of the sphere= $\frac{4}{3}\pi r^3$

Volume of atom = V

$V=\frac{4}{3}\times 3.14\times (8.6\times 10^{-14} cm)^3=2.664\times 10^{-39}cm^3$

Mass of proton, m = 1.0073 amu = $1.0073\times 1.66054\times 10^{-24} g$

$1 amu = 1.66054\times 10^{-24} g$

Density of the proton : d

$d=\frac{m}{V}=\frac{1.0073\times 1.66054\times 10^{-24} g}{2.664\times 10^{-39}cm^3}=6.278\times 10^{14} g/cm^3$

The density of a proton is $6.278\times 10^{14} g/cm^3$ .

5 0

3 years ago

According to KMT, at constant pressure and temperature, the frequency and force of molecule-wall collisions are constant. So inc

Norma-Jean [14]

Answer:

Boyle´s Law

Explanation:

If we increase the volume of a gas, its pressure will decrease that is why in this question the pressure was decreased to yield the decrease in the number of collisions.

This is Boyle´s law which states that the pressure of a gas is inversely proportional to the volume of its container.

It is expressed mathematically as P₁V₁ = P₂V₂

where the subscripts refer to intial and final conditions.

3 0

3 years ago