Answer:1 mol of Mg(NO3)2 contains 6.022*10^23 molecules
3 mol Mg(NO3)2 contains 3*6.022*10^23 = 1.81*10^24 molecules
Each Mg(NO3)2 molecule contains 2 N atoms
Number of N atoms = 2*1.81*10^24 = 3.62*10^24 N atoms.
Answer:
I and IV are the correct answers
Explanation:
Answer:
.500
Explanation:
Use the ideal gas law equation: PV = nRT
Plug in the initial values given:
P = 1.2 atm
V = .500 L
n = number of moles
R = Gas Constant 8.314
T = 25.0 C
(1.2)(.5) = n(8.314)(25)
solving for n we get .00289
Now use the same equation with the new values solving for V
(3.6)V = (.00289)(8.314)(75.0)
V = .4999999 ROund to .500
