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Airida [17]
3 years ago
10

Is it possible to have a bent molecule without a molecular dipole?

Chemistry
1 answer:
s2008m [1.1K]3 years ago
3 0

Answer:

no but that is what we were taught

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Who discovered electrons using Crookes tube?
andrey2020 [161]

Answer:

William Crookes????????????????

4 0
3 years ago
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Read the statement.
Rudiy27

Answer:

300 gr.

Explanation:

if 204gr/100gr=solubility, then according to the condition solubility=612/x.

It means, 204/100=612/x, where x=612*100/204=300 gr.

6 0
3 years ago
Which of the following could you do to increase the strength of an electromagnet?
notsponge [240]

Change the core from wood to iron. This is because iron is a magnetic material while wood is not magnetic hence cant acquire magnetism. Other factors that would increase the strength of electromagnet would be; increasing the amount of electric current, and increasing the number of winding's.

6 0
3 years ago
Which change in oxidation number indicates oxidation? A) Ito +2 C +2 to -3 B) Ito -2 D) +3 to +2
tatuchka [14]

As there is the increase in Oxidation number from +1 to +2. Hence, the correct Option (A) i.e, 1 to +2,

<h3>What is Oxidation ?</h3>

Oxidation doesn't necessarily have anything to do with oxygen.

  • Oxidation occurs when an atom, molecule, or ion loses one or more electrons in a chemical reaction.
  • When oxidation occurs, the oxidation state or oxidation number of the chemical species increases.
  • Oxidation doesn't necessarily involve oxygen! Originally, the term was used when oxygen caused electron loss in a reaction.

Hence, Option (A) indicates the oxidation as there is the increase in Oxidation number from +1 to +2.

Learn more about Oxidation here ;

brainly.com/question/13110055

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3 0
2 years ago
The Ksp of CaF2 is 4.0 x 10-11. What is the solubility of CaF2 in 0.10 M Ca(NO3)2? Give your answer using scientific notation an
Ilya [14]

Answer:

1.0\times 10^{-5} M is the solubility of CaF_2 in 0.10 M Ca(NO_3)_2.

Explanation:

Concentration of calcium nitrate = [Ca(NO_3)_2]=0.10 M

Ca(NO_3)_2\rightarrow Ca^{2+}+2NO_3^{-}

[Ca(NO_3)_2]=0.10 M=[Ca^{2+}]

Solubility product of the calcium fluoride = K_{sp}=4.0\times 10^{-11}

Solubility of calcium fluoride in calcium nitrate solution :

CaF_2\rightleftharpoons Ca^{2+}+2F^-

            (0.10+S)   (2S)

The expression of solubility is given by :

K_{sp}=[Ca^{2+}][F^-]^2

4.0\times 10^{-11}=(S+0.10)(2S)^2

Solving for S:

S=1.0\times 10^{-5} M

1.0\times 10^{-5} M is the solubility of CaF_2 in 0.10 M Ca(NO_3)_2.

3 0
3 years ago
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