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Airida [17]
3 years ago
10

Is it possible to have a bent molecule without a molecular dipole?

Chemistry
1 answer:
s2008m [1.1K]3 years ago
3 0

Answer:

no but that is what we were taught

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9.The industrial preparation of hydrogen gas from water gas is referred to as​
natima [27]

Answer: Bosch process

Explanation:

Bosch process is an industrial process for the manufacture of H2. This proces uses cheap raw materials( water and coke) to generate water gas which is mixed with water in the presence of a catalyst(iron(II) oxide or chromium(iii) oxide) to generate H2

6 0
4 years ago
Amy performed an experiment in lab. She improperly mixed the chemicals, and an explosion of light, sound, and heat occurred. Whe
agasfer [191]

The answer is D transformed

4 0
4 years ago
Which of the following would be expected to dissolve readily in the nonpolar solvent CCl4?
ratelena [41]

<em>The given answer would dissolve readily in the nonpolar solvent CCl4;</em>

D. Grease

<u>Because water molecules are polar, they interact with the sodium and chloride ions. In general, polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes. </u>

3 0
4 years ago
In completing a Fischer Esterification experiment using acetic acid and unknown alcohol catalyzed by sulfuric acid a student sta
masha68 [24]

Answer:

The equilibrium law

Explanation:

According to the equilibrium law , when $\text{concentration}$ of any of the  reactants or the products in the reaction at an equilibrium state,  is changed, then it changes the composition of equilibrium mixture in order to minimize the effect of

Acetic acid (in excess) + $\text{alcohol}$ ⇄  $\text{ester}$ + water

$\text{Fischer esterification}$ is a reaction which involves the equilibrium. So to force the reaction towards the side of $\text{ester}$, one of the reactant is taken in excess. All this can be explained easily by applying the equilibrium law.

3 0
3 years ago
A piece of fossilized wood has a carbon-14 radioactivity that is 1/4 that of new wood. the half-life of carbon-14 is 5730 years.
Marizza181 [45]

Answer:

1.146 x 10⁴ year.

Explanation:

  • The decay of carbon-14 is a first order reaction.
  • The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
  • The integration law of a first order reaction is:

<em>kt = ln [A₀]/[A]</em>

<em></em>

k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.

t is the time = ??? years.

[A₀] is the initial percentage of carbon-14 = 100.0 %.

[A] is the remaining percentage of carbon-14 = 1/4[A₀] = 25.0 %.

∵ kt = ln [Ao]/[A]

∴ (1.21 x 10⁻⁴ year⁻¹)(t) = ln (100.0%)/[25.0 %]

(1.21 x 10⁻⁴ year⁻¹)(t) = 1.386.

∴ <em>t </em>= 1.386/ (1.21 x 10⁻⁴ year⁻¹) =  <em>1.146 x 10⁴ year.</em>

3 0
4 years ago
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