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sweet-ann [11.9K]
3 years ago
12

Which two are present in both waxes and sphingomyelin? select all that apply. select all that apply. glycerol fatty acid phospha

te long-chain alcohol carbohydrate?
Chemistry
1 answer:
maks197457 [2]3 years ago
8 0
The compounds that are present in both waxes and sphingomylin are FATTY ACID AND LONG CHAIN ALCOHOL.
Waxes are diverse type of organic substances which are hydrophobic in nature and they are found in both plant and animals. Sphingomyelin is a type of sphingolipid, which are found in animal cell membranes. It is especially abundant in the  membranous myelin sheath which surround some nerve cells.<span />
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You have to prepare 100.0 mL of a 0.100 M solution of sodium carbonate. You have a concentrated solution of sodium carbonate tha
Georgia [21]

Answer:

6.9 ml of concentrate

Explanation:

100 ml   of .1 M   will require .01 moles

from a 1.45 M solution,  .01 mole would be

  .01 mole / ( 1.45 mole / liter) = 6.9 ml of the concentrate   then dilute to 100 ml

4 0
2 years ago
An unknown triprotic acid (H3A) is titrated with NaOH. After the titration Ka1 is determined to be 0.0013 and Ka2 is determined
e-lub [12.9K]

Answer:

6.68 X 10^-11

Explanation:

From the second Ka, you can calculate pKa = -log (Ka2) = 6.187

The pH at the second equivalence point (8.181) will be the average of pKa2  and pKa3. So,

8.181 = (6.187 + pKa3) / 2

Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11

7 0
3 years ago
Need help with the 1st one
lutik1710 [3]

If I’m right this should be the answer

7 0
3 years ago
PLS HELP NOW WILL GIVE BRAINLIEST
zvonat [6]

Answer:

Liquids, because they flow, can occupy whatever shape their container has, so they do not have a fixed shape. Because the particles in liquids are very close together (barely further apart than in solids) liquids do not easily compress, so their volume is fixed. hope that helps love!

7 0
3 years ago
Lead can be prepared from galena [lead(II) sulfide] by first roasting the galena in oxygen gas to form lead(II) oxide and sulfur
Vesna [10]

Answer:

a) Step 1:

2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)

Step 2:

2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)

b) The overall balanced reaction for given process is ;

3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)

Explanation:

a)

Galena = PbS

Lead(II) oxide = PbO

Sulfur dioxide = SO_2

Step 1:

Roasting the galena in oxygen gas to form lead(II) oxide and sulfur dioxide.

Balanced equation of step 1:

2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)..[1]

Step 2:

Heating the metal oxide with more galena forms the molten metal and more sulfur dioxide.

Balanced equation of step 2:

2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)..[2]

b)

For over all reaction add [1] and [2]. The overall balanced reaction for given process is ;

3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)

5 0
4 years ago
Read 2 more answers
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