It's highly reactive and contains only one valence electron
Answer:
![5.04\cdot 10^8 A](https://tex.z-dn.net/?f=5.04%5Ccdot%2010%5E8%20A)
Explanation:
The work function of the metal corresponds to the minimum energy needed to extract a photoelectron from the metal. In this case, it is:
![\phi = 3.950\cdot 10^{-19}J](https://tex.z-dn.net/?f=%5Cphi%20%3D%203.950%5Ccdot%2010%5E%7B-19%7DJ)
So, the energy of the incoming photon hitting on the metal must be at least equal to this value.
The energy of a photon is given by
![E=\frac{hc}{\lambda}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7Bhc%7D%7B%5Clambda%7D)
where
h is the Planck's constant
c is the speed of light
is the wavelength of the photon
Using
and solving for
, we find the maximum wavelength of the radiation that will eject electrons from the metal:
![\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{3.950\cdot 10^{-19} J}=5.04\cdot 10^{-7}m](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7Bhc%7D%7BE%7D%3D%5Cfrac%7B%286.63%5Ccdot%2010%5E%7B-34%7D%20Js%29%283%5Ccdot%2010%5E8%20m%2Fs%29%7D%7B3.950%5Ccdot%2010%5E%7B-19%7D%20J%7D%3D5.04%5Ccdot%2010%5E%7B-7%7Dm)
And since
1 angstrom = ![10^{-15}m](https://tex.z-dn.net/?f=10%5E%7B-15%7Dm)
The wavelength in angstroms is
![\lambda=\frac{5.04\cdot 10^{-7} m}{10^{-15} m/A}=5.04\cdot 10^8 A](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7B5.04%5Ccdot%2010%5E%7B-7%7D%20m%7D%7B10%5E%7B-15%7D%20m%2FA%7D%3D5.04%5Ccdot%2010%5E8%20A)
S=56, u=0, v=33, a=?, t=3.4
v=u+at
33=3.4 a
a = 9.7m/s^2
Answer:
two people who are not going to be able to make it to class today because of the day and then I will be there at the house and then we can go
In a collision, there is a force on both objects that causes an acceleration of both objects; the forces are equal in magnitude and opposite in direction. For collisions between equal-mass objects, each object experiences the same acceleration.