All categories

2 years ago

I WILL MARK BRAINLIEST!Which of the following statements is true?

Chemistry

2 answers:

PtichkaEL [24]2 years ago

6 0

Answer:

B- fission breaks apart nuclei; fusion puts them back together

frez [133]2 years ago

6 0

Answer:

The correct answer is option B.

Explanation:

Fission is a process in which nuclei breaks apart into two. It is also called as nuclear fission. It can be controlled or uncontrolled process in this process high amount of energy release.

Thus, the correct answer is option B.

* Hopefully this helps:) Mark me the brainliest:)!!!

You might be interested in

Of the following choices, pick all that are uses for radiation. Check all that

Novosadov [1.4K]

A B C these are the answers hopes this help <3

8 0

2 years ago

Determine the heat energy needed to raise the temperature of 120 grams of ice at -5 to steam at 115°

CaHeK987 [17]

Answer:

Q = 30355.2 J

Explanation:

Given data:

Mass of ice = 120 g

Initial temperature = -5°C

Final temperature = 115°C

Energy required = ?

Solution:

Specific heat capacity of ice is = 2.108 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Q = m.c. ΔT

ΔT = T2 -T1

ΔT = 115 - (-5°C)

ΔT = 120 °C

Q = 120 g × 2.108 j/g.°C × 120 °C

Q = 30355.2 J

5 0

3 years ago

What's the chemistry definition of density

Paha777 [63]

Density is defined as the ratio between mass and volume or mass per unit volume.
Source is google

5 0

2 years ago

The rate constant k for a certain reaction is measured at two different temperatures temperature 376.0 °c 4.8 x 108 280.0 °C 2.3

9966 [12]

Answer:

The activation energy for this reaction = 23 kJ/mol.

Explanation:

Using the expression,

$\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )$

Where,

$k_1\ is\ the\ rate\ constant\ at\ T_1$

$k_2\ is\ the\ rate\ constant\ at\ T_2$

$E_a$ is the activation energy

R is Gas constant having value = 8.314×10⁻³ kJ / K mol

$k_2=2.3\times 10^8$

$T_2=280\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (280 + 273.15) K = 553.15 K

$T_2=553.15\ K$

$k_1=4.8\times 10^8$

$T_1=376\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (376 + 273.15) K = 649.15 K

$T_1=649.15\ K$

So,

$\left(\ln \left(\:\frac{4.8\times \:\:\:10^8}{2.3\times \:\:\:10^8}\right)\right)\:=-\frac{E_a}{8.314\times \:10^{-3}\ kJ/mol.K}\times \:\left(\frac{1}{649.15\ K}-\frac{1}{553.15\ K}\right)$

$E_a=-\frac{10^{-3}\times \:8.314\ln \left(\frac{10^8\times \:4.8}{10^8\times \:2.3}\right)}{-\frac{96}{359077.3225}}\ kJ/mol$

$E_a=-\frac{\frac{8.314\ln \left(\frac{4.8}{2.3}\right)}{1000}}{-\frac{96}{359077.3225}}\ kJ/mol$

$E_a=22.87\ kJ/mol$

The activation energy for this reaction = 23 kJ/mol.

6 0

2 years ago

A sample of gas exerts a pressure of 16 atm at a temperature of 340 K. What is the pressure of the gas in atm if the temperature

gavmur [86]

Answer:

P2 = 19.2atm

Explanation:

Initial pressure (P1) = 16atm

Initial temperature (T1) = 340K

Final temperature (T2) = 408K

Final pressure (P2) = ?

This question involves the use of pressure law

Pressure law states that the pressure of a fixed mass of gas is directly proportional to it's temperature provided that volume is kept constant.

Mathematically,

P = kT, k = P / T

Therefore,

P1 / T1 = P2 / T2 = P3 / T3 = ......=Pn / Tn

P1 / T1 = P2 / T2

We need to solve for P2

P2 = (P1 × T2) / T1

Now we can plug in the values and solve for P2

P2 = (16 × 408) / 340

P2 = 6528 / 340

P2 = 19.2atm

The final pressure (P2) of the gas is 19.2atm

5 0

3 years ago