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love history [14]
3 years ago
15

Which of the following is an example of increasing friction intentionally? a. waxing skis b. adding grease to gears on a bike c.

throwing sand on an icy driveway d. oiling a squeaky door Please select the best answer from the choices provided
Physics
1 answer:
Aleonysh [2.5K]3 years ago
7 0
C i think that it tell me if its wrong
You might be interested in
Do all of them please and explain
kondaur [170]

At 305 and 309 it was negative because it is going down


at 300 and 301 and 305 it was positive because its going up


at 302/303/304/306/309 she wasn't accelerating at all because it is staying the same

5 0
3 years ago
Read 2 more answers
A body of mass 80kg was lifted vertically through a distance of 5.0 metres. Calculate the work done on the body. ( Acceleration
sleet_krkn [62]

Answer:

80×5×10=4000J

so therefore, work done on the body is 4000J

8 0
3 years ago
A cup of water is warmed from 21 °C to 85 °C. What is the difference between these two temperatures, in kelvins?
Ilya [14]

Answer:

337k

Explanation:

First, let us find the difference between the given two temperatures.

Difference = 85°C - 21°C

                  = 64°C

<u>And now we have to write the temperature in kelvins.</u>

To convert Celcius to Kelvins you can add 273 to the temperature in Celcius.

<u>Let us find it now.</u>

64°C + 273 = 337k

Therefore,

64°C ⇒ <u>337k</u>

8 0
2 years ago
Ocean waves are hitting a beach at a rate of 3.5 Hz. What is the period of the waves?
Radda [10]

Answer:

the correct answer is 0.286 s

5 0
3 years ago
A scientist directs monochromatic light toward a single slit in an opaque barrier. The light has a wavelength of 580 nm and the
vredina [299]

Answer:

a) 9.72 mm

b) 4.86 mm

Explanation:

wave length of light  λ is  580 nm = 580 \times 10⁻⁹ m

Width of slit d = 0.215\times 10⁻³ m

Distance of screen D  = 1.8 m.

Width of one fringe = \frac{\lambda\times D}{d}

Putting the values we get fringe width

= \frac{580\times10^{-9}\times1.8}{.000315}

=4.86 mm.

a) Width of central maxima = 2 times width of one fringe

= 2 times 4.86

=9.72 mm

b) width of each fringe except central fringe  is same , no matter what the order is.Only brightness changes .

So width of either of the two first order bright fringe will be same and it will be  

= 4.86 mm.

3 0
3 years ago
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