In mechanics, the normal force<span> is the component, perpendicular to the surface (surface being a plane) of contact, of the contact </span>force<span> exerted on an object . We calculate as follows:
</span>∑F along x = 0 = F - Fn
<span>
Fn = F = mg = 7.52(9.81) = 73.77 N <------OPTION B</span>
Answer:
along the lead, at right angles to the lead at the middle, and at right angles to the lead at one end.
<u>Answer:</u>
The time taken for the ball to hit the floor as 1.02 seconds
<u>Explanation:</u>
As per the given question, the ball leaves at a speed from the table with an initial velocity of 10 m/s, we have the equation
where Vf represents the final velocity
Vi represents the initial velocity
a represents the acceleration and
t represents the time
after rearranging
= 1.022 seconds
Answer:
120 N
Explanation:
F=ma therefore 60kg times 2m/s^2 is 120 N
Answer:
a)0.48 m/s
b) 0.583 m/s
Explanation:
As the wagon rolls,
momentum'p'= m x v => 95.8 x 0.530 = 50.774 Kgm/s
(a)Rock is thrown forward,
momentum of rock = 0.325 x 15.1 = 4.9075 Kgm/s
Conservation of momentum says momentum of wagon is given by
50.774 - 4.9075 = 45.8665
Therefore, Speed of wagon = 45.8665 / (95.8-0.325) = 0.48 m/s
(b) Rock is thrown backward,
momentum of wagon = 50.774 + 4.9075 = 55.68 Kgm/s
Therefore, speed of wagon = 55.68 / (95.8-0.325) = 0.583 m/s