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A car on a freeway speeds up to get around another car. The car speeds up from 20 m/s to 35 m/s in 5 seconds.

Tanzania [10]

Answer:

Initial speed = 20 m/s

Final speed = 35 m/s

Time to speed up = 5 seconds

Explanation:

Directly from the information given:

Initial speed = 20 m/s

Final speed = 35 m/s

Time to speed up = 5 seconds

5 0

3 years ago

Encuentra la masa molar<br><br> TO<br><br> de 65 litros de SO2

shepuryov [24]

La masa molar de 65 litros de SO2 es igual a 64,1 g/mol.

<h3>Masa molar</h3>

La masa molar de un compuesto depende de su masa presente en 1 mol, entonces:

$MM=\frac{m}{mol}$

Para calcular la masa molar de un compuesto, simplemente suma las masas de cada elemento en el compuesto, así:

$MM_O = 16g/mol\\MM_S= 32.1g/mol$

$32.1 + 2\times 16 = 64.1g/mol$

Así, la masa molar de 65 litros de SO2 es igual a 64,1 g/mol.

Obtenga más información sobre la masa molar en: brainly.com/question/17109809

8 0

3 years ago

Your friend says that the force that the sun exerts on earth is much larger than the force that earth exerts on the sun. part a

Verizon [17]

I disagree with that opinion, and I have solid Physics to back me up.

The forces of gravity are always equal in both directions. The sun pulls the Earth with exactly the same force with which the Earth pulls the sun.

It may seem weird, but your weight on Earth is exactly the same as the Earth's weight on you. For the same reason.

8 0

3 years ago

Read 2 more answers

A body of mass m, = 0.050 kg and initial velocity v₁ = 9 m / s turned to the right collides with a body of mass m₂ = 0.030 g wit

Ugo [173]

Answer:

Suppose two objects of different masses are moving with different velocities in the same direction on a straght-line before collision. After collision, they stick together and move with common (the same) velocity

6 0

2 years ago

A cylindrical cistern, constructed below ground level, is 2.9 m in diameter and 2.0 m deep and is filled to the brim with a liqu

Tomtit [17]

Answer:

15.1 m

Explanation:

We first calculate the apparent depth from

refractive index, n = real depth/apparent depth

apparent depth, a = real depth/refractive index

real depth = 2.0 m, refractive index = 1.4

apparent depth, a = 2.0/1.4 = 1.43 m

Since the cylindrical cistern has a diameter of 2.9 m, its radius is 2.9/2 = 1.45 m

The angle of refraction, r is thus gotten from the ratio

tan r = radius/apparent depth = 1.45/1.43 = 1.014

r = tan⁻¹(1.014) = 45.4°

The angle of incidence, i is gotten from n = sin i/sin r

sin i = nsin r = 1.4sin45.4° = 1.4 × 0.7120 = 0.9968

i = sin⁻¹(0.9968) = 85.44°

Since the girl's eyes are 1.2 m from the ground, the distance ,h from the edge of the cistern she must stand is gotten from

tan i = h/1.2

h = 1.2tan i = 1.2tan85.44° = 1.2 × 12.54 = 15.05 m

h = 15.05 m ≅ 15.1 m

So, she must stand 15.1 m away from the edge of the cistern to still see the object.

4 0

3 years ago