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An electron is moving horizontally east in an electric field that points vertically downward. The electric force on the electron

saveliy_v [14]

Answer:

d. )directed upward.

Explanation:

As the electron has a negative charge, when under the influence of an electric field, is subject to an electric force, which direction is the opposite to the direction of the electric field.

This is because the electric field has the same direction that the force on a positive test charge at the same point.

As the electric field points vertically downward, the electric force on the electron (a negative charge) points vertically upward.

So, the statement d. is the one that results to be true.

7 0

3 years ago

If the radius of the sun is 7.001×105 km, what is the average density of the sun in units of grams per cubic centimeter? The vol

xenn [34]

Answer:

Average density of Sun is 1.3927 $\frac{g}{cm}$ .

Given:

Radius of Sun = 7.001 × $10^{5}$ km = 7.001 × $10^{10}$ cm

Mass of Sun = 2 × $10^{30}$ kg = 2 × $10^{33}$ g

To find:

Average density of Sun = ?

Formula used:

Density of Sun = $\frac{Mass of Sun}{Volume of Sun}$

Solution:

Density of Sun is given by,

Density of Sun = $\frac{Mass of Sun}{Volume of Sun}$

Volume of Sun = $\frac{4}{3} \pi r^{3}$

Volume of Sun = $\frac{4}{3} \times 3.14 \times [7.001 \times 10^{10}]^{3}$

Volume of Sun = 1.436 × $10^{33}$ $cm^{3}$

Density of Sun = $\frac{ 2\times 10^{33} }{1.436 \times 10^{33} }$

Density of Sun = 1.3927 $\frac{g}{cm}$

Thus, Average density of Sun is 1.3927 $\frac{g}{cm}$ .

4 0

3 years ago

A car tire is filled with air at pressure 325000 pa at 303 K. When the tire cools,its pressure reduces to 299000 Pa. What is the

max2010maxim [7]

Answer:

new temperature of the tire will be 278.76 K

Explanation:

when the temperature increases, the particles will have greater kinetic energy and also the pressure will be increase for the gas particles.

so when the temperature increases, pressure will also increase and vice versa

T is directly proportional to P

T1 = initial temperature= 303 k

P1= Initial pressure = 325000 pa

T2= Final temperature= ?

P2= Final pressure = 299000 pa

mathematically

P1/T1= P2/T2

T2= P2 x T1/P1

T2 = 299000 x 303/ 325000= 278.76 k

6 0

4 years ago

Read 2 more answers

Three sharks are located at the vertices of an equilateral triangle whose side equals LL. They all start moving simultaneously w

salantis [7]

Answer:

They will never meet.

Explanation:

Given that three sharks are located at the vertices of an equilateral triangle whose side equals LL. They all start moving simultaneously with a constant speed vv, with the first shark heading constantly toward the second, the second toward the third, and the third toward the first. How soon will the sharks converge at one point ?

Since the three sharks are located at the vertices of an equilateral triangle whose side equals, and the first shark is moving toward the second, the second is moving toward the third, and the third shark is moving toward the first, the movement of the three shark will form a circular motion.

Since the three sharks are moving at a constant speed, the three sharks will never meet because the distances between them are also the same.

The three sharks will therefore continue to move till infinity.

6 0

3 years ago

A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the cable for the following case

Murljashka [212]

Answer:

The answer is below

Explanation:

A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the

cable for the following cases:

a. The load moves downward at a constant velocity

b. The load accelerates downward at a rate 0.4 m/s??

C. The load accelerates upward at a rate 0.4 m/s??

Solution:

Acceleration due to gravity (g) = 10 m/s²

a) Given that the mass of the crane (m) is 140 kg. If the load moves downward, the tension (T) is given by:

mg - T = ma

Since the load has a constant velocity, hence acceleration (a) = 0. Therefore:

mg - T = m(0)

mg - T = 0

T = mg

T = 140(10) = 1400 N

T = 1400 N

b) If the load moves downward, the tension (T) is given by:

mg - T = ma

T = mg - ma = m(g - a)

T = 140(10 - 0.4) = 140(9.96) = 134.4

T = 134.4 N

c) If the load moves upward, the tension (T) is given by:

T - mg = ma

T = ma + mg = m(a + g)

T = 140(0.4 + 10) = 140(10.4)

T = 145.6 N

2) To find the distance (s) if the load move from rest (u= 0) and accelerates for 20 seconds (t = 20). We use:

s = ut + (1/2)gt²

s = 0(20) + (1/2)(10)(20)²

s = 2000 m

7 0

3 years ago