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Ksivusya [100]
3 years ago
9

A ball that is thrown upwards from the ground will eventually reach its highest point and fall back to the ground. Which of the

following quantities will be constant over the course of this up and down motion?
a. The ball's position.b. The ball's speed.c. The ball's acceleration.d. Nonsense! None of these are constant.
Physics
1 answer:
tia_tia [17]3 years ago
5 0

Answer:

option (c)

Explanation:

When an object thrown upwards, the value of acceleration acting on the object is acceleration due to gravity which is always acting towards the earth.

As it falls downwards, the acceleration is again equal to the acceleration due to gravity.

So, the ball's acceleration is constant.

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According to Einstein's special theory of relativity, in which frames of reference will all laws of physics apply?
kenny6666 [7]

Answer: Within any frame of reference that is accelerating

Special relativity was proposed on 1905 by Einstein, who developed his theory based on the following two postulates:

1. <em>The laws of physics are the same in all inertial systems. There is no preferential system. </em>

2. <em>The speed of light in vacuum has the same value for all inertial systems. </em>

Focusing on the first postulate, it can be affirmed that <u>any measurement on a body is made with reference to the system in which it is being measured</u>.

Now, taking into account that an inertial reference system is the one that complies with the principle of inertia:

<em>"For a body to have acceleration, an external force must act on it."</em>

The correct answer is  

Within any frame of reference that is accelerating

3 0
3 years ago
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Please select the word from the list that best fits the definition
lianna [129]

Answer: No list

Explanation:

7 0
3 years ago
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An object is 70 um long and 47.66um wide. how long and wide is the object in km?​
Ganezh [65]

Answer:

length =  7*10^(-8)km

width = 4.666*10^(-8) km

Explanation:

We know that:

1 μm = 1*10^(-6) m

and

1km = 1*10^3 m

or

1m = 1*10^(-3) km

if we replace the meter in the first equation, we get:

1 μm = 1*10^(-6)*1*10^(-3) km

1 μm = 1*10^(-6 - 3)km

1 μm = 1*10^(-9)km

Now with this relationship we can transform our measures:

Length: 70 μm is 70 times 1*10^(-9)km, or:

L = 70*1*10^(-9)km = 7*10^(-8)km

And for width, we have 47.66um, this is 46.66 times 1*10^(-9)km, or:

W = 46.66*1*10^(-9)km = 4.666*10^(-8) km

7 0
3 years ago
An airplane pilot wishes to fly due west. A wind of 80.0 km/h (about 50 mi/h) is blowing toward the south. (a) If the airspeed o
Vesnalui [34]

Answer:

a) 75.5 degree relative to the North in north-west direction

b) 309.84 km/h

Explanation:

a)If the pilot wants to fly due west while there's wind of 80km/h due south. The north-component of the airplane velocity relative to the air must be equal to the wind speed to the south, 80km/h in order to counter balance it

So the pilot should head to the West-North direction at an angle of

cos(\alpha) = 80/320 = 0.25

\alpha = cos^{-1}(0.25) = 1.32 rad = 180\frac{1.32}{\pi} = 75.5^0 relative to the North-bound.

b) As the North component of the airplane velocity cancel out the wind south-bound speed. The speed of the plane over the ground would be the West component of the airplane velocity, which is

320sin(\alpha) = 320sin(75.5^0) = 309.84 km/h

7 0
3 years ago
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It took 500 newtons of force to push a car 4 meters. How much work was done?
Ede4ka [16]
Work = Force x Distance = 500 x 4 = 2000 Nm = 2000 J
3 0
2 years ago
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