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GaryK [48]
3 years ago
6

1.24 moles of magnesium arsenate are dissolved in 1.74 kg of solution. Calculate the molality of the solution.

Chemistry
1 answer:
aleksklad [387]3 years ago
6 0

Answer:

Molality of the solution = 0.7294 M

Explanation:

Given:

Number of magnesium arsenate = 1.24 moles

Mass of solution = 1.74 kg

Find:

Molality of the solution

Computation:

Molality of the solution = Mole of solute / Mass of solution = 1.74 kg

Molality of the solution = 1.24 / 1.7

Molality of the solution = 0.7294 M

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3 years ago
43 mg = [?]g <br>A. 0.043 g <br>B. 4.3 g <br>C. 4300 g <br>D. 43,000 g​
Ymorist [56]

Answer:

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Explanation:

Given:

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1 \ mg = \frac{1}{1000} \ g

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3 years ago
In beta decay, what is emitted? A. an electron B. a helium-4 atom C. a neutron D. a photon E. a radionucleus
myrzilka [38]

Answer: A. an electron

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How many atoms are there in 32.45 grams of Magnesium?
levacccp [35]

Answer:

8.13 ×10²³ atoms

Explanation:

Given data:

Mass of magnesium = 32.45 g

Number of atoms = ?

Solution:

Number of moles of Mg:

Number of moles = mass/molar mass

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Number of atoms:

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8.13 ×10²³ atoms

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