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GaryK [48]
2 years ago
6

1.24 moles of magnesium arsenate are dissolved in 1.74 kg of solution. Calculate the molality of the solution.

Chemistry
1 answer:
aleksklad [387]2 years ago
6 0

Answer:

Molality of the solution = 0.7294 M

Explanation:

Given:

Number of magnesium arsenate = 1.24 moles

Mass of solution = 1.74 kg

Find:

Molality of the solution

Computation:

Molality of the solution = Mole of solute / Mass of solution = 1.74 kg

Molality of the solution = 1.24 / 1.7

Molality of the solution = 0.7294 M

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melamori03 [73]
It changes from a liquid from to a solid.

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3 0
2 years ago
Part A:
uranmaximum [27]

Answer:

Part A = The mass of sulfur is 6.228 grams

Part B = The mass of 1 silver atom is 1.79 * 10^-22 grams

Explanation:

Part A

Step 1: Data given

A mixture of carbon and sulfur has a mass of 9.0 g

Mass of the product = 27.1 grams

X = mass carbon

Y = mass sulfur

x + y = 9.0  grams

x = 9.0 - y

x(molar mass CO2/atomic mass C) + y(molar mass SO2/atomic mass S) = 22.6

(9 - y)*(44.01/12.01) + y(64.07/32.07)

(9-y)(3.664) + y(1.998)

32.976 - 3.664y + 1.998y = 22.6

-1.666y = -10.376

y = 6.228 = mass sulfur

x = 9.0 - 6.228 = 2.772 grams = mass C

The mass of sulfur is 6.228 grams

Part B

Calculate the mass, in grams, of a single silver atom (mAg = 107.87 amu ).

Calculate moles of 1 silver atom

Moles = 1/ 6.022*10^23

Moles = 1.66*10^-24 moles

Mass = moles * molar mass

Mass = 1.66*10 ^-24 moles *107.87

Mass = 1.79 * 10^-22 grams

The mass of 1 silver atom is 1.79 * 10^-22 grams

5 0
2 years ago
Read 2 more answers
1.24 moles of magnesium arsenate are dissolved in 1.74 kg of solution. Calculate the molality of the solution.
aleksklad [387]

Answer:

Molality of the solution = 0.7294 M

Explanation:

Given:

Number of magnesium arsenate = 1.24 moles

Mass of solution = 1.74 kg

Find:

Molality of the solution

Computation:

Molality of the solution = Mole of solute / Mass of solution = 1.74 kg

Molality of the solution = 1.24 / 1.7

Molality of the solution = 0.7294 M

6 0
2 years ago
What is the significance sodium hydroxide and hydrochloric acid
hammer [34]

Answer:

They are a base and an acid,  so they neutralize each other.

Explanation:

Sodium hydroxide is a strong base. Hydrochloric acid is a strong acid.

They react with (neutralize) each other to form a salt (sodium chloride) and water.

NaOH + HCl ⟶ NaCl + H₂O

5 0
2 years ago
Write the balanced oxidation-reduction reaction equation for the oxidation of benzoin by ammonium nitrate. 2
Margarita [4]
<span>Benzoin<span> is an organic compound with the formula PhCH(OH)C(O)Ph. It is a hydroxy ketone attached to two phenyl groups.</span><span>

To answer your question, </span><span>the balanced oxidation-reduction reaction equation for the oxidation of benzoin by ammonium nitrate is:

</span>2Ph-C(OH)-C(O)-Ph+NH4NO3 --> 2Ph-C(O)-C(O)-Ph + N2 + 3H2O.</span>

<span>
</span><span>I hope this helps and if you have any further questions, please don’t hesitate to ask again.</span>

7 0
3 years ago
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