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asambeis [7]
3 years ago
15

Question 3

Chemistry
1 answer:
Assoli18 [71]3 years ago
8 0

Answer:

c

Explanation:

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As the frequency of a wave generated by a radio transmitter is increased ,the wavelength
bazaltina [42]
For waves velocity (v) is equal to the wavelength (λ) times frequency (f). (They are inversely proportional)

V=λf

Since V is constant, if frequency increases, wavelength decreases.
5 0
3 years ago
Which statement regarding liquids is true? 1.can be converted to solids by adding energy in the form of heat 2.occupy a definite
GuDViN [60]

Answer:

4.occupy a definite volume while taking the shape of their container.

Explanation:

Since the particles in a liquid are quite close together (not as close as a solid) they have a definete volume,  and the particles are still able to move around as they wish they have no definite shape and take upon the shape of the container they are placed in.

8 0
3 years ago
Write the equation for the dissolution of sodium carbonate in water as found in your laboratory guide.
Arisa [49]
Na₂CO₃(s) → 2Na⁺(aq) + CO₃²⁻(aq)
The sodium carbonate formed from a strong base and a weak acid. Hydrolysis is subjected to the anion of a weak acid.

CO₃²⁻ + H₂O ⇄ HCO₃⁻ + OH⁻
HCO₃⁻ + H₂O ⇄ H₂CO₃ + OH⁻

pH>7 alkaline solution

2Na⁺ + CO₃²⁻ + 2H₂O ⇄ 2Na⁺ + 2OH⁻ + H₂CO₃
3 0
3 years ago
How did Rutherford's gold foil experiment show that Thomson's plum pudding model of the atom was
Ket [755]

Answer:

He blasted alpha rays at the gold foils. The Alpha rays are charged positive. When he blasted them the protons deflected and changed the course of them and the electrons surrounding the atom let them through. In the plum pudding model they were supposed to be sprinkled on which was clearly wrong according to that experiment.

Explanation:

6 0
3 years ago
An aqueous solution of potassium sulfate (K2SO4) has a freezing point of -2.24
iragen [17]
An aqueous solution of potassium sulfate exhibits colligative properties. Colligative properties are properties that depends on the concentration of a substance in a solution. These properties are freezing point depression, vapor pressure lowering, osmotic pressure and boiling point elevation. For this problem we use the concept of freezing point depression since we are given the freezing point of the solution. Freezing point depression is as:
 
ΔT = -k(f) x m x i
-2.24 - 0 = -1.86 x m x 3
<span>m = 0.4014

Thus, the molality of the solution is 0.4014.</span>
7 0
3 years ago
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