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<u>Answer:</u> The pH of the solution is 12.61
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
......(1)
- <u>For hydrazoic acid:</u>
Molarity of hydrazoic acid solution = 1.200 M
Volume of solution = 242.5 mL
Putting values in equation 1, we get:
- <u>For NaOH:</u>
Molarity of NaOH solution = 0.3400 M
Volume of solution = 1006 mL
Putting values in equation 1, we get:
The chemical reaction for hydrazoic acid and NaOH follows the equation:
<u>Initial:</u> 0.291 0.342
<u>Final:</u> 0 0.051 0.291 0.291
Volume of solution = 242.5 + 1006 = 1248.5 mL = 1.2485 L (Conversion factor: 1 L = 1000 mL)
- <u>For NaOH left:</u>
Left moles of NaOH = 0.051 moles
Volume of the solution = 1.2485 L
Putting values in equation 1, we get:
1 mole of NaOH produces 1 mole of sodium ions and 1 mole of hydroxide ions
To calculate pOH of the solution, we use the equation:
We are given:
Putting values in above equation, we get:
To calculate pH of the solution, we use the equation:
Hence, the pH of the solution is 12.61