The last one is true.
Lets say that wave 1 has function of W1 = A*sin(w*t) and second one
W2 = A*(w*t - 180)
both waves have same amplitude A and same frequency (w=2*pi*f)
in t=0 first wave has value of 0 and second one has value of 0. Their sum is equal to 0.
As the time starts passing first wave's value will grow while second one will decrease and go negative (because of the shape of sinus function). Both of them are changing their value at same rate because of same frequency and their sum will always be 0. Check the graph.
Answer:
the regular daily rises and falls in sea level caused by the gravitational attraction of the Moon and Sun on Earth.
Explanation:
Tides can be defined as the rise and fall of water level in water bodies such as lakes and oceans due to the gravitational force of attraction exerted by the moon on earth. The side closest to the moon creates a bulge of water known as high tide. Low tides are generally experienced when a sea level is not within the bulge.
Generally, the gravitational pull of the Moon cause visible changes on planet Earth's surface.
This ultimately implies that, the pull of the Moon's gravity causes high and low tides on planet Earth's surface.
The various types of ocean tides based on the position of the Earth, Moon and the Sun are;
I. Neap tides.
II. Spring tides.
III. Low tide.
IV. High tide.
V. Brown tide.
VI. Rip tide.
VII. Red tide.
During mitosis<span>, a eukaryotic cell undergoes a carefully coordinated nuclear division that results in the formation of two genetically identical daughter cells.</span>
The sudden flow of electricity between two electrically charged objects caused by contact, an electrical short, or dielectric breakdown. A buildup of static electricity can be caused by tribocharging or by electrostatic induction.
Answer:
823.46 kgm/s
Explanation:
At 9 m above the water before he jumps, Henri LaMothe has a potential energy change, mgh which equals his kinetic energy 1/2mv² just as he reaches the surface of the water.
So, mgh = 1/2mv²
From here, his velocity just as he reaches the surface of the water is
v = √2gh
h = 9 m and g = 9.8 m/s²
v = √(2 × 9 × 9.8) m/s
v = √176.4 m/s
v₁ = 13.28 m/s
So his velocity just as he reaches the surface of the water is 13.28 m/s.
Now he dives into 32 cm = 0.32 m of water and stops so his final velocity v₂ = 0.
So, if we take the upward direction as positive, his initial momentum at the surface of the water is p₁ = -mv₁. His final momentum is p₂ = mv₂.
His momentum change or impulse, J = p₂ - p₁ = mv₂ - (-mv₁) = mv₂ + mv₁. Since m = Henri LaMothe's mass = 62 kg,
J = (62 × 0 + 62 × 13.28) kgm/s = 0 + 823.46 kgm/s = 823.46 kgm/s
So the magnitude of the impulse J of the water on him is 823.46 kgm/s
