Answer:
<u>The function is:</u>
<u>According to data in the table we have:</u>
- f(1) = 3 ⇒ a(1)ⁿ = 3 ⇒ a*1 = 3 ⇒ a = 3
- f(2) = 12 ⇒ 3*2ⁿ = 12 ⇒ 2ⁿ = 4 ⇒ n = 2
<u>Since we found the values of a and n, the function becomes:</u>
<u>The number of infected to the tenth day:</u>
Answer:
(ab+a-b+1)(ab-a+b+1)
Step-by-step explanation:
- (1 - a²) (1 - b²) + 4ab=
- 1 -a²-b² +a²b² +4ab =
- (a²b² +2ab +1 )- (a²-2ab+b²)=
- (ab+1)² - (a-b)²=
- (ab+1 +a-b)(ab+1 -a+b)=
- (ab+a-b+1)(ab-a+b+1)
The value of cos(A+B) is 36/325.
<h3>What is Trigonometry?</h3>
The branch of mathematics concerned with specific functions of angles and their application to calculations.
Given:
cos(A)=−5/13
sin(B)=7/25
Now Using identity,
sin²A + cos² A= 1
sin A= √1 - cos² A
sin A = √1- 25/169
sin A= √144/169
sin A= 12/13
Again,
sin²B + cos² B= 1
cos B= √1 - sin² B
cos B = √1- 49/625
cos B= √576/625
cos B= -24/25
Now,
cos (A +B) = cos A cos B - sin A sin B.
= -5/13* (-24/25) - 12/13* 7/25
= 120/325 - 84/325
= 36/325
Hence, the value of cos (A + B) is 36/325.
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The lower and upper limit of the 95% confidence interval is 183.2 and 196.0 unit.
What is a confidence interval ?
When you run your experiment again or resample the population in the same way, you can expect your estimate to fall within a certain range of values a certain percentage of the time. This is known as the confidence interval.
Main Body:
Given in question :
x- bar = 189.6
standard deviation = 10
C.I. = 95% =0.95
N=12
so, degree of freedom (D.F) = N-1 = 11
confidence level (α) = (1- C.I.)/2
= 0.025
according to t- distribution table for d.f = 11 and α= 0.025 , my result is 2.201
Now dividing standard deviation by square root of samples, we get
= 10/√12= 2.887
Lower limit = Mean - 2.201*2.887
= 189.6- 6.354
= 183.246
Upper limit = Mean + 2.201*2.887
= 189.6 + 6.354
= 195.954
Hence the result is 183.2 and 196.
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Answer:
A, the correct answer is A