Answer:
The heat of vaporisation of methanol is "3.48 KJ/Mol"
Explanation:
The amount of heat energy required to convert or transform 1 gram of liquid to vapour is called heat of vaporisation
When 8.7 KJ of heat energy is required to vaporize 2.5 mol of liquid methanol.
Hence, for 1 mol of liquid methanol, amount of heat energy required to evaporate the methanol is =
= 3.48 KJ
So, the heat of vaporization
Therefore, the heat of vaporization of methanol is 3.48KJ/Mol
<span>Density
is a value for mass, such as kg, divided by a value for volume, such as m3.
Density is a physical property of a substance that represents the mass of that
substance per unit volume. We calculate as follows:
Density = mass of gasoline/ volume of gasoline = (1</span>46.770 g -110.525 g ) / <span>50 ml = 0.7249 g/mL</span>
Answer:
C. soluble
Explanation:
Remember that a substance that dissolves in a solvent is said to be soluble in that solvent. A substance that does not dissolve in a solvent is insoluble. Process of Dissolving: Solvent particles surround solute particles to form a solution in a process called solvation.
Answer:
Yah, it's true.
because protons are represented as helium (²4He) which are positive.
electrons are represented as 0-1e which is negative
Answer:
I am pretty sure Danny Duncan told me 69
Explanation:
niice