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s344n2d4d5 [400]
4 years ago
12

There are always attractive forces between a collection of atoms or molecules which may not be negligible as suggested by the ki

netic molecular theory. The strength of these forces depend upon the nature of the atom or molecule. If a mole of gas is at STP and there are very strong attractive intermolecular forces between the gas particles, the volume will be _________.
Chemistry
1 answer:
Harrizon [31]4 years ago
7 0

Answer:

Negligible

Explanation:

According to the kinetic theory of gases, the degree of intermolecular interaction between gases is minimal and gas molecules tend to spread out and fill up the volume of the container.

If the attraction between gas molecules increases, then the volume of the gas decreases accordingly. This is because, gas molecules become highly attracted to each other.

This intermolecular attractive force may be so strong, such that the actual volume of the gas become negligible compared to the volume of the container.

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Balance the chemical equation by indicating the number of each species in the appropriate blanks. For this exercise, indicate co
ch4aika [34]

Answer:

3 Fe (s) + 4 H2O (l) -----> Fe3O4 (s) + 4 H2 (g)

Explanation:

your question is not completed , perhaps the question is similar to this solution, you can use it .

The balanced equation is

3 Fe (s) + 4 H2O (l) -----> Fe3O4 (s) + 4 H2 (g)

Explanation: In order to balance an equation we must ensure that the number of atoms of each species on right side of the arrow must be equal to the number of atoms of each species on left side of the arrow.

8 0
4 years ago
I need help please i need to pass
goldfiish [28.3K]
Energy was released.
4 0
4 years ago
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Boyle's Law for gases is:
larisa86 [58]

Answer:

b. just a model and therefore accurate for no real gases

Explanation:

Boyle´s Law was determined and is applied for ideal gases, this is, those gases that:

- Do not have any interaction between their particles (neither attraction nor repulsion)

- Any collision between its particles is perfectly elastic

With these conditions, Boyle found that pressure and volume (in a constant temperature) are inversely proportional, which can be expressed as:

PV = k, where “k” is a constant

So, when pressure increases, volume decreases, and viceversa.  

If we have to different conditions (1 and 2) of pressure and volume (at constant temperature), this can be expressed like:

P₁V₁ = P₂V₂ = constant

The current and complete equation that links temperature, pressure, mass (in moles) and volume is:

PV = nRT

Real gases do not strictly comply with this law, as its particles has interactions and collisions are not perfectly elastic. This law is more accurate for gases with low molecular mass, and with low pressure and/or high temperature conditions (under these conditions, interactions can be neglected)

Another term that can gives us an idea whether a gas is ideal or not, is the compressibility coefficient Z:

Z = PV/RT

For ideal gases, Z = 1 , as long as the gas moves away from ideality, Z is totally different from 1

3 0
3 years ago
Please Help! Thank You
matrenka [14]

Answer: cancel

Explanation:

6 0
3 years ago
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(LO 3N, 4G, 4O) Aluminum sulfate is also involved in dying fabrics. The gelatinous precipitate formed in the reaction with dilut
brilliants [131]

9.4 × 10⁻³ mg (0.73 mmoles) of Al(OH)₃ is formed

Explanation:

We have the following chemical reaction:

Al₂(SO₄)₃(aq) + 6 NaOH(aq) → 2 Al(OH)₃(s) + 3 Na₂SO₄(aq)

The precipitate mentioned by the problem is aluminium hydroxide Al(OH)₃.

Now to determine the number of moles of sodium hydroxide NaOH we use the following formula:

molar concentration =  number of moles / volume

number of moles = molar concentration × volume

number of moles of NaOH = 0.088 M × 25 mL = 2.2 mmoles

number of moles of Al₂(SO₄)₃ = 5.6 × 10⁻³ moles = 5.6 mmoles (found in the  problem text)

We see from the chemical reaction that 1 mole of Al₂(SO₄)₃ requires 6 moles of NaOH so 5.6 mmoles of Al₂(SO₄)₃ would require 6 times more NaOH which is 33.6 mmoles and we have only 2.2 mmoles. The limiting reactant will be NaOH.

Now we devise the following reasoning:

if        6 mmoles of NaOH produces 2 mmoles of Al(OH)₃

then  2.2 mmoles of NaOH produces X mmoles of Al(OH)₃

X = (2.2 × 2) / 6 = 0.73 mmoles of Al(OH)₃

mass of Al(OH)₃ = number of moles / molecular weight

mass of Al(OH)₃ = 0.73 / 78

mass of Al(OH)₃ =  9.4 × 10⁻³ mg

Learn more:

precipitation reaction

brainly.com/question/10400269

7 0
3 years ago
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