What is it a b c or d

Which is an aspect of the kinetic-molecular theory and can be used to explain the compressibility of plasma

tekilochka [14]

The answer choice which represents an aspect of the kinetic-molecular theory and can be used to explain compressibility of plasma is; Particles move independently of one another and are widely spaced.

<h3>What is the kinetic-molecular theory?</h3>

The kinetic-molecular theory in discuss postulates about the states of matter.

Also, it is built upon the idea that matter is composed of tiny particles that are constantly in motion.

Hence, the theory is explanatory of the observable properties and behaviours of solids, liquids and gases and hence, explains the compressibility of plasma.

Remarks;

Particles move independently of one another and are widely spaced.
Particle kinetic energy increases with increasing temperature.
Particles exert no attractive or repulsive force on one another.
Particles always move even when they have fixed positions.

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4 0

1 year ago

hat historical figure was responsible for developing the system for categorizing living things that is still used today? A) Sir

VladimirAG [237]

Carolus Linnaeus is responsible.

3 0

3 years ago

How many molecules OF2 would have a mass of .132 g

BlackZzzverrR [31]

<h3>Answer:</h3>

1.47 × 10²¹ molecules OF₂

<h3>General Formulas and Concepts: </h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation: </h3>

<u>Step 1: Define</u>

0.132 g OF₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of O - 16.00 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of OF₂ - 16.00 + 2(19.00) = 54.00 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 0.132 \ g \ OF_2(\frac{1 \ mol \ OF_2}{54.00 \ g \ OF_2})(\frac{6.022 \cdot 10^{23} \ molecules \ OF_2}{1 \ mol \ OF_2})$
Divide/Multiply: $\displaystyle 1.47204 \cdot 10^{21} \ molecules \ OF_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.47204 × 10²¹ molecules OF₂ ≈ 1.47 × 10²¹ molecules OF₂

3 0

3 years ago

Two molecules have the same molecular geometry but different electron domain geometries. Which combination of atoms and lone pai

m_a_m_a [10]

The correct answer is:
2 atoms and 2 lone pairs; 2 atoms and 1 lone pair.
Both AX₂E₂ and AX₂E have different electron domain geometry; AX₂E₂ is tetrahedral and AX₂E is trigonal planar but both of them has the same molecular geometry Bent

4 0

3 years ago

Read 2 more answers

explain the relationship between the rate of effusion of a gas and its molar mass. methane gas (ch4) effuses 3.4 times faster th

Musya8 [376]

The molar mass of the unknown gas is 184.96 g/mol

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>How to determine the molar mass of the unknown gas </h3>

The following data were obtained from the question:

Rate of unknown gas (R₁) = R
Rate of CH₄ (R₂) = 3.4R
Molar mass of CH₄ (M₂) = 16 g/mol
Molar mass of unknown gas (M₁) =?

The molar mass of the unknown gas can be obtained as follow:

R₁/R₂ = √(M₂/M₁)

R / 3.4R = √(16 / M₁)

1 / 3.4 = √(16 / M₁)

Square both side

(1 / 3.4)² = 16 / M₁

Cross multiply

(1 / 3.4)² × M₁ = 16

Divide both side by (1 / 3.4)²

M₁ = 16 / (1 / 3.4)²

M₁ = 184.96 g/mol

Learn more about Graham's law of diffusion:

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3 0

2 years ago