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3 years ago

Which of the following is the best example of kinetic energy being transformed into potential energy?

Chemistry

1 answer:

galben [10]3 years ago

5 0

Answer:

The correct answer is A

Explanation:

That water stops moving once it gets to the dam and turns into potential energy

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When you heat a substance what happens to the molecules

tatyana61 [14]

I'm pretty sure they come closer, and on the small chance i'm wrong, they separate.<span />

6 0

3 years ago

Read 2 more answers

Which of the following statements is true? Oceanic crust is thicker than continental crust. Both oceanic and continental crust i

zhuklara [117]

The crust is the thickest layer of the Earth.

3 0

3 years ago

When a solution containing 1.4000 g of Ba(NO3)2 and 2.4000 g of HSO3NH2 is boiled, a precipitate forms. One possible identity fo

Georgia [21]

Answer:

See explanation for detailed solution

Explanation:

The balanced reaction equation is Ba(NO3)2 + 2HSO3NH2 → Ba(SO3NH2)2 + 2HNO3

Number of moles of Ba(NO3)2 = 1.4 g/ 261.337 g/mol = 5.36 × 10^-3 moles

From the reaction equation;

1 mole of Ba(NO3)2 yields 1 mole of Ba(SO3NH2)2

5.36 × 10^-3 moles of Ba(NO3)2 yields 5.36 × 10^-3 moles of Ba(SO3NH2)2

For HSO3NH2

Number of moles = 2.4g/97.10 g/mol =0.0247 moles

2 moles of HSO3NH2 yields 1 mole of Ba(SO3NH2)2

0.0247 moles of HSO3NH2 yields 0.0247 ×1/2 = 0.0137 moles

Hence, Ba(NO3)2 is the limiting reactant

The theoretical yield of Ba(SO3NH2)2 is 5.36 × 10^-3 moles × 329.4986 g/mol = 1.766 g

Number of moles = mass/ molar mass

Molar mass = mass/ number of moles

Molar mass = 1.6925 g/5.36 × 10^-3 moles = 315.76 g

3 0

3 years ago

If a sample of magnesium with a mass of 35.0 grams reacts with 35.0 grams of oxygen how much magnesium oxide will be produced?

slamgirl [31]

Answer:

58.0 g of MgO

Explanation:

in a perfect world, 70 g, however we don't live in a perfect world

The equation of reaction

2Mg + O₂ --> 2MgO

first find which element is limiting:

35 g x 1 mol/24.3 g of Mg x 2 mol of MgO/ 2 mole of Mg = 1.44 moles of MgO

35 g x 1 mol/32g of Mg x 2 mol of MgO/ 1 mole of O₂ = 2.1875 moles of MgO

This means Mg is the limiting factor, so you will be using this moles to find grams of MgO

1.44 mols of MgO x 40.3 g of MgO/ 1 mol = 58.0 g of MgO

8 0

3 years ago

A reaction at -6.0 °C evolves 786. mmol of sulfur tetrafluoride gas. Calculate the volume of sulfur tetrafluoride gas that is co

borishaifa [10]

Answer:

V of Sulfur tetrafluoride is 17.2 L

Explanation:

Given data;

T = -6°C = 267K [1° C = 273 K]

n = 786 mmol of SF4 which is 0.786 mol

P = 1 atm

from ideal gas law we have

PV = nRT

where n is mole, R is gas constant, V is volume

$V = \frac{nRT}{P}$ $V = \frac{0.786 mol \times 0.082 atmL/mol K \times* 267K}{1atm} = 17.2 L$

V of Sulfur tetrafluoride is 17.2 L

6 0

3 years ago