Question

Estimate the crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) , if the wavelength of maximum absorption for the ion is 600 nm. [Note: This is a high-field (low-spin) complex.]

Answer 1

Answer:

The crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) , if the wavelength of maximum absorption for the ion is 600 nm is - 1987.59kJ/mole

Explanation:

Lets calculate -:

 Crystal field stabilization energy -

                    $E=\frac{hc}{\pi }$

   where h = planks constant = $6.626\times10^-^3^4 Js$

             c= velocity of light = $3\times10^8m/second$

           $\pi =wavelength=600nm=600\times10^-^9m$

           $E=\frac{6.626\times10^-^3^4\times3\times10^8}{600\times10^-^9}$

                =$0.033\times10^-^1^6 J/ion$

              = $0.033\times10^-^1^6\times6.023\times10^2^3$

             = $0.198759\times10^7 J/mole$  = $1987.59\times10^3J/mole$

             = $1987.59kJ/mole$

 Thus , the crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) is  1987.59kJ/mole