Answer: air
Explanation:since individual components of air cannot be identified by merely looking at it, it is a homogeneous mixture.
Using the given formula, the density of the material is 2.015 g/mL
<h3>Calculating Density </h3>
From the question, we are to determine the density of the material
From the given formula
Density = Mass / Volume
And from the given information,
Mass = 65.5 g
and volume = 32.5 mL
Putting the parameters into the equation,
Density = 65.5/32.5
Density = 2.015 g/mL
Hence, the density of the material is 2.015 g/mL.
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Answer:
M₂ = 0.08 M
Explanation:
Given data:
Initial volume = 25.0 mL
Initial molarity = 0.500 M
Final volume = 150.0 mL
Final molarity = ?
Solution:
Formula:
M₁V₁ = M₂V₂
0.500 M × 25.0 mL = M₂ × 150.0 mL
M₂ = 0.500 M × 25.0 mL / 150.0 mL
M₂ = 12.5 M.mL /150.0 mL
M₂ = 0.08 M
Displaced volume:
final volume - initial volume
1 mL = 1 cm³
38.5 mL - 35.0 mL = 3.5 cm³
hope this helps!
Answer:
b. 2.28 M
Explanation:
The reaction of neutralization of NaOH with H2SO4 is:
2NaOH + H2SO4 → Na2SO4 + 2H2O
<em>Where 2 moles of NaOH react per mole of H2SO4</em>
<em />
To solve the concentration of NaOH we need to find the moles of H2SO4. Using the chemical equation we can find the moles of NaOH that react and with the volume the molar concentration as follows:
<em>Moles H2SO4:</em>
45.7mL = 0.0457L * (0.500mol/L) = 0.02285 moles H2SO4
<em>Moles NaOH:</em>
0.02285 moles H2SO4 * (2moles NaOH / 1 mol H2SO4) = 0.0457moles NaOH
<em>Molarity NaOH:</em>
0.0457moles NaOH / 0.020L =
2.28M
Right option:
<h3>b. 2.28 M</h3>
