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vovangra [49]
3 years ago
10

) palmitic acid is a 16 carbon acid. in a balanced equation, the products of the saponification of glyceryl tripalmitate (tripal

mitin) are
Chemistry
1 answer:
lesya [120]3 years ago
8 0

Answer: The products of the saponification of glyceryl tripalmitate (tripalmitin) are one molecule of glycerol and three molecules of sodium salt of palmitic acid.

Explanation:

A chemical reaction in which triglycerides react with sodium hydroxide and leads to the formation of one molecule of glycerol and three molecules of a salt of fatty acid is known as saponification.

For example, when tripalmitin reacts with sodium hydroxide then it leads to the formation of one molecule of glycerol and three molecules of sodium salt of palmitic acid.

The reaction equation is as follows.

   C_{51}H_{98}O_{6} + NaOH \rightarrow C_{3}H_{8}O_{3} + 3C_{16}H_{31}O_{2}Na^{+}

Thus, we can conclude that the products of the saponification of glyceryl tripalmitate (tripalmitin) are one molecule of glycerol and three molecules of sodium salt of palmitic acid.

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What is the result when atoms combine in fixed ratios?
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Answer:

Chemical reaction

Explanation:

4 0
3 years ago
How many Faradays of electricity are carried by 1.505×10^23 electronsk​
aksik [14]

Mole of electron required by 1.505 *10^{23} mole is 2.5* 10  ^{-1}

  • Faraday law expressed how the  change that is been being produced by a current at an electrode-electrolyte interface is related and  proportional to the quantity of electricity  that is been used.

  • There is one mole of electron required for 1 Faraday of electricity.

  • Avogadro constant is 6.02*10^{23}

  • Mole of electron can be calculated by dividing the number of electron by avogadro's constant.

=\frac{1.505*10^{23} }{6.02*10^{23} }

= 2.5* 10^{-1}  Faraday  of electricity

Therefore, it requires  2.5*10^{-1} Faraday of electricity for the 1.505 *  10^{23}  mole.

Learn more at: brainly.com/question/1640558?referrer=searchResults

3 0
2 years ago
Protons and neutrons are found in the nucleus. these two types of charges are referred to collectively as _____
solmaris [256]

Answer:

Nucleon

Explanation:

4 0
3 years ago
Write the balanced equation for the equilibrium reaction for the dissociation ofsilver chloride in water, and write the K expres
Marizza181 [45]

Answer:

See explanation

Explanation:

Hello there!

In this case, since the the concentrations are not given, and not even the Ksp, we can solve this problem by setting up the chemical equation, the equilibrium constant expression and the ICE table only:

AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)

Next, the equilibrium expression according to the produced aqueous species as the solid silver chloride is not involved in there:

Ksp=[Ag^+][Cl^-]

And therefore, the ICE table, in which x stands for the molar solubility of the silver chloride:

       \ \ \ \ \ \ \ \ \ \ \ \ \ \ AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)

I          -                   0             0

C        -                   +x           +x

E        -                    x             x

Which leads to the following modified equilibrium expression:

Ksp=x^2

Unfortunately, values were not given, and they cannot be arbitrarily assigned or assumed.

Regards!

6 0
2 years ago
Balance this equation: Al+ HNO3 ---- H2 + Al(NO3)3​
romanna [79]

Answer:

2Al+ 6HNO3 ---- 3H2 + 2Al(NO3)3​

Explanation:

Put coefficient a,b,c, and d for calculation:

a Al + b HNO3 = c H2 + d Al(NO3)3

for Al: a = d

for H: b = 2c

for N: b = 3d

for O: 3b = 9d

Suppose a=1, then d=1, b=3, c=3/2

multiply 2 to make all natural number, a=2, then b=6, c=3, d=2

6 0
3 years ago
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