Answer:
Yes such a frame exists: a free-fall (free-float frame) frame. This frame of reference is subject only to gravity and no forces such as electromagnetic forces or nuclear forces.
Answer:
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2. by trying and solving
by not giving
by innovating
by being motivated
BY KNOWING THAT U CAN DO IT
Answer:
1)
2)
3)
4)
Explanation:
1)
We can use the following equation:
Here, the initial velocity in the y-direction is zero, the final y position is zero and the initial y position is 25 m.
2)
The equation of the motion in the x-direction is:
3)
The velocity in the y-direction of the stone will be:
Now, the velocity in the x-direction is 15 m/s then the velocity will be:
4)
The angle of this velocity is:
Then α=55.92° negative from the x-direction.
I hope it helps you!
The solution for this problem is:
r = [(2.90 + 0.0900t²) i - 0.0150t³ j] m/s²
this is for t in seconds and r in meters
v = dr/dt = [0.180t i - 0.0450t² j] m/s²
tan(-36.0º) = -0.0450t² / 0.180t
0.7265 = 0.25t
t = 2.91 s is the velocity vector of the insect
Answer:
Explanation:
How long does the football need to rise?
4.70/3 = 2.35 s
What height will the football reach?
h = ½(9.81)2.35² = 27.1 m
With what speed does the punter need to kick the football?
vy = g•t = 9.81(2.35) = 23.1 m/s
vx = d/t = 56.0/4.70 = 11.9 m/s
v = √(vx²+vy²) = 26.0 m/s
At what angle (θ), with the horizontal, does the punter need to kick the football?
θ = arctan(vy/vx) = 62.7°
