Answer:
32.76 Volt
Explanation:
frequency, f = 400 Hz
Area of crossection, A = 13 cm²
Maximum flux density, B = 0.9 tesla
Number of turns in secondary coil, N = 70
Let the maximum induced voltage is e.
According to the Faraday's law of electromagnetic induction, the induced emf is equal to the rate of change of magnetic flux.
e = dФ/dt
![e=\frac{NBA}{t}](https://tex.z-dn.net/?f=e%3D%5Cfrac%7BNBA%7D%7Bt%7D)
Time is defined as the reciprocal of frequency.
So, e = N B A f
e = 70 x 0.9 x 13 x 10^-4 x 400
e = 32.76 volt
Answer:
a. 79.1 N
b. 344 J
c. 344 J
d. 0 J
e. 0 J
Explanation:
a. Since the crate has a constant velocity, its net force must be 0 according to Newton's 1st law. The push force
by the worker must be equal to the friction force
on the crate, which is the product of friction coefficient μ and normal force N:
Let g = 9.81 m/s2
![F_p = F_f = \mu N = \mu mg = 0.26 * 31 * 9.81 = 79.1 N](https://tex.z-dn.net/?f=F_p%20%3D%20F_f%20%3D%20%5Cmu%20N%20%3D%20%5Cmu%20mg%20%3D%200.26%20%2A%2031%20%2A%209.81%20%3D%2079.1%20N)
b. The work is done on the crate by this force is the product of its force
and the distance traveled s = 4.35
![W_p = F_ps = 79.1*4.35 = 344 J](https://tex.z-dn.net/?f=W_p%20%3D%20F_ps%20%3D%2079.1%2A4.35%20%3D%20344%20J)
c. The work is done on the crate by friction force is also the product of friction force and the distance traveled s = 4.35
![W_f = F_fs = -79.1*4.35 = -344 J](https://tex.z-dn.net/?f=W_f%20%3D%20F_fs%20%3D%20-79.1%2A4.35%20%3D%20-344%20J)
This work is negative because the friction vector is in the opposite direction with the distance vector
d. As both the normal force and gravity are perpendicular to the distance vector, the work done by those forces is 0. In other words, these forces do not make any work.
e. The total work done on the crate would be sum of the work done by the pushing force and the work done by friction
![W_p + W_f = 344 - 344 = 0 J](https://tex.z-dn.net/?f=W_p%20%2B%20W_f%20%3D%20344%20-%20344%20%3D%200%20J)
Ith air resistance acting on an object that has been dropped, the object will eventually reach a terminal velocity, which is around 53 m/s (195 km/h or 122 mph) for a human skydiver. ... (On the Moon, the gravitational acceleration is much less than on Earth, approximately 1.6 m/s2.)
Answer:
<em>50 m/s</em>
<em></em>
Explanation:
In a projectile motion, acceleration is only on the vertical plane, that is, the vertical velocity is the only velocity component that undergoes acceleration under gravitational force. The horizontal component of velocity dos not change with time, and hence is the same as the initial velocity of the projectile.