The maximum shear stress in the tube when the power is transmitted through a 4: 1 gearing is 28.98 MPa.
<h3>What is power?</h3>
Power is the energy transferred per unit time.
Torque is find out by
P = 2πNT/60
10000 = 2π x 2000 x T / 60
T =47.74 N.m
The gear ratio Ne / Ns =4/1
Ns =2000/4 = 500
Ts =Ps x 60/(2π x 500)
Ts =190.96 N.m
Maximum shear stress τ = 16/π x (T / (d₀⁴ - d₁⁴))
τ max =T/J x D/2
where d₁ = 30mm = 0.03 m
d₀ = 30 +(2x 4) = 38mm =0.038 m
Substitute the values into the equation, we get
τ max = 16 x 190.96 x 0.038 /π x (0.038⁴ - 0.03⁴)
τ max = 28.98 MPa.
Thus, the maximum shear stress in the tube is 28.98 MPa.
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Answer:
over a rive or fast moving water or canyon
Explanation: you would use a suspension bridge in an area where you can't put supports down.
Answer:
Head loss=0.00366 ft
Explanation:
Given :Water flow rate Q=0.15 
= 6 inch=0.5 ft
=2 inch=0.1667 ft
As we know that Q=AV
So 
=0.687 ft/sec
We know that Head loss due to sudden contraction
If nothing is given then take K=0.5
So head loss
=0.00366 ft
So head loss=0.00366 ft
