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prisoha [69]
3 years ago
13

Which statement is true about endothermic and exothermic reactions

Chemistry
1 answer:
AfilCa [17]3 years ago
4 0

Answer:

The products have less potential energy than the reactants in an exothermic reaction.

Explanation:

took the test

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HELP!!!!!!!!!!!! ASAP!!!!!!!!!!!!!!!!!!! CHEMISTRY TEST!!!!!!!!!!!!!! 53 POINTS
lbvjy [14]

Answer:

9.1 KJ

Explanation:

First we must find the number of moles of HBr involved;

number of moles of HBr= mass of HBr/ molar mass of HBr

But molar mass of HBr= 80.91 g/mol

Given mass of HBr from the question= 20.1g

Hence;

Number of moles of HBr= 20.1 g/80.91g

Number of moles of HBr= 0.25 moles of HBr

If 2 moles of HBr has a heat of formation of 72.80KJ

Then 0.25 moles of HBr will have a heat of formation of 0.25× 72.80/2= 9.1 KJ

Therefore; 20.1 g of HBr will have a heat of formation of 9.1 KJ

3 0
3 years ago
Vinegar is an aqueous solution of acetic acid, ch3cooh. a 5.00 ml sample of a particular vinegar requires 26.90 ml of 0.175 m na
Fed [463]

  The molarity  of  acetic acid in the  vinegar is  0.94 M


 <u><em> calculation</em></u>

Step 1:  write  the balanced equation between CH3COOH  + NaOH

that is CH3COOH   + NaOH  →  CH3COONa  + H2O


step 2 :  find the moles of NaOH

moles  =molarity  x volume in L

volume in liters = 26.90/1000=0.0269 l

moles = 0.175 mol /L x 0.0269 L  =0.0047  moles  of NaOH


Step 3: use the mole  ratio to find moles of CH3COOH

that is the  mole ratio of  CH3COOH: NaOH is 1:1 therefore  the moles of CH3COOH is  =0.0047  moles


Step 4:  find the  molarity  of  CH3COOH

molarity = moles/volume in liters

volume in liter = 5.00/1000 =0.005 l

molarity  is therefore=0.0047 moles/ 0.005 l = 0.94 M

4 0
4 years ago
Put all chemicals down the drain. True or false?
Dovator [93]
False, many chemicals can be toxic to the drainage systems, and can make their way into the ocean harming sea life. 
4 0
3 years ago
Read 2 more answers
An ordered list of chemical substances is shown.
Alex73 [517]

answer : the correct option is, (B) 2, 3 and 6.

3 0
3 years ago
A mysterious compoud with the chemical formula MX (Ksp 1.27x10-36) is present in two different solutions. What is its molar solu
qwelly [4]

<u>Answer:</u> The molar solubility of MX is 2.54\times 10^{-36}M

<u>Explanation:</u>

We are given:

K_{sp}(MX)=1.27\times 10^{-36}

The chemical equation for the ionization of MX follows:

MX\rightleftharpoons M^+(aq.)+X^-(aq.)

                  S         S

The expression of K_{sp} for above equation is:

K_{sp}=S\times S      ......(1)

The chemical equation for the ionization of M_2SO_4 follows:

M_2SO_4\rightleftharpoons 2M^+(aq.)+SO_4^{2-}(aq.)

 0.25M           0.5M      0.25M

Total concentration of cation from both the equation is:

[M^+]=0.5+S

As, K_{sp}(MX), so S is also very very less than 1 and can be easily neglected.

So, [M^+]=0.5M

Putting values in equation 1, we get:

1.27\times 10^{-36}=0.5\times S\\\\S=2.54\times 10^{-36}M

Hence, the molar solubility of MX is 2.54\times 10^{-36}M

4 0
3 years ago
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