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3 years ago

A,b, e are complete. Help on the others would be so appreciated!!

Physics

1 answer:

bixtya [17]3 years ago

8 0

Answer:

serie Ceq=0.678 10⁻⁶ F and the charge Q = 9.49 10⁻⁶ C

Explanation:

Let's calculate all capacity values

a) The equivalent capacitance of series capacitors

1 / Ceq = 1 / C1 + 1 / C2 + 1 / C3 + 1 / C4 + 1 / C5

1 / Ceq = 1 / 1.5 + 1 / 3.3 + 1 / 5.5 + 1 / 6.2 + 1 / 6.2

1 / Ceq = 1 / 1.5 + 1 / 3.3 + 1 / 5.5 + 2 / 6.2

1 / Ceq = 0.666 + 0.3030 +0.1818 +0.3225

1 / Ceq = 1,147

Ceq = 0.678 10⁻⁶ F

b) Let's calculate the total system load

Dv = Q / Ceq

Q = DV Ceq

Q = 14 0.678 10⁻⁶

Q = 9.49 10⁻⁶ C

In a series system the load is constant in all capacitors, therefore, the load in capacitor 5.5 is Q = 9.49 10⁻⁶ C

c) The potential difference

ΔV = Q / C5

ΔV = 9.49 10⁻⁶ / 5.5 10⁻⁶

ΔV = 1,725 V

d) The energy stores is

U = ½ C V²

U = ½ 0.678 10-6 14²

U = 66.4 10⁻⁶ J

e) Parallel system

Ceq = C1 + C2 + C3 + C4 + C5

Ceq = (1.5 +3.3 +5.5 +6.2 +6.2) 10⁻⁶

Ceq = 22.7 10⁻⁶ F

f) In the parallel system the voltage is maintained

Q5 = C5 V

Q5 = 5.5 10⁻⁶ 14

Q5 = 77 10⁻⁶ C

g) The voltage is constant V5 = 14 V

h) Energy stores

U = ½ C V²

U = ½ 22.7 10-6 14²

U = 2.2 10⁻³ J

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