Molecules, The movemnet of molecules
Answer:
(a): The resultant force acting on the object are F= (5.99 i + 14.98 j).
(b): The magnitude of the resultant force are F= 16.4 N < 68.19º .
Explanation:
m= 3kg
a= 2 i + 5 j = 5 .38 < 68.19 º
F= m * a
F= 3* ( 5.38 < 68.19º )
F= 16.4 N < 68.19º
Fx= F * cos(68.19º)
Fx= 5.99
Fy= F* sin(68.19º)
Fy= 14.98
- Initial velocity (u) = 0 m/s [the car was at rest]
- Distance (s) = 80 m
- Time (t) = 10 s
- Let the magnitude of acceleration be a.
- By using the equation of motion,
we get,![80 = 0 \times 10 + \frac{1}{2} \times a \times {10}^{2} \\ = > 80 = \frac{1}{2} \times 100a \\ = > 80 = 50a \\ = > a = \frac{80}{50} \\ = > a = 1.6](https://tex.z-dn.net/?f=80%20%3D%200%20%5Ctimes%2010%20%2B%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%20a%20%5Ctimes%20%20%7B10%7D%5E%7B2%7D%20%20%5C%5C%20%20%3D%20%20%3E%2080%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%20100a%20%5C%5C%20%20%3D%20%20%3E%2080%20%3D%2050a%20%5C%5C%20%20%3D%20%20%3E%20a%20%3D%20%20%5Cfrac%7B80%7D%7B50%7D%20%20%5C%5C%20%20%3D%20%20%3E%20a%20%3D%201.6)
<u>A</u><u>nswer:</u>
<u>The </u><u>magnitude</u><u> </u><u>of </u><u>its </u><u>acceleration</u><u> </u><u>is </u><u>1</u><u>.</u><u>6</u><u> </u><u>m/</u><u>s^</u><u>2</u><u>.</u>
Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer:
false
Explanation:
the answer is false bc for a non-polar bond to form the electrons are shared equally...