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Shtirlitz [24]
3 years ago
15

The coordinate of a particle in meters is given by x(t) = 16t − 3.0t3, where the time t is in

Physics
1 answer:
Advocard [28]3 years ago
7 0

Answer:

t = -4/3 s, t = 4/3 s

Explanation:

I am ASSUMING that you want to know the time(s) the particle is at rest.

and that your position equation is x(t) = 16t − 3.0t³

IF those assumptions are true

THEN

velocity is the derivative of position

v(t) = 16 - 9t²

the particle will be at rest when velocity is zero

0 = 16 - 9t²

9t² = 16

t² = 16/9

t = ± 4/3

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Vector A= 3.7 i + 1.0 j and vector B = 3.0 i + 6.5 j. What is vector<br> (A-B).A?
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dot product:

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Now let's solve our problem, we have:

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              = (3.7 - 3.0, 1.0 - 6.5).(3.7, 1.0)

              = (0.7, -5.5).(3.7, 1.0) = (0.7*3.7) + (-5.5)*(1.0) = -2.91

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