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Shtirlitz [24]
3 years ago
15

The coordinate of a particle in meters is given by x(t) = 16t − 3.0t3, where the time t is in

Physics
1 answer:
Advocard [28]3 years ago
7 0

Answer:

t = -4/3 s, t = 4/3 s

Explanation:

I am ASSUMING that you want to know the time(s) the particle is at rest.

and that your position equation is x(t) = 16t − 3.0t³

IF those assumptions are true

THEN

velocity is the derivative of position

v(t) = 16 - 9t²

the particle will be at rest when velocity is zero

0 = 16 - 9t²

9t² = 16

t² = 16/9

t = ± 4/3

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A linear equation is of the form y = Gx

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x = \left[\begin{array}{ccc}100\end{array}\right]

\left[\begin{array}{ccc}102*10^{-3} \\97*10^{-3}  \end{array}\right] =  \left[\begin{array}{ccc}G_{1} \\G_{2}  \end{array}\right] \left[\begin{array}{ccc}100\end{array}\right]\\\left[\begin{array}{ccc}G_{1} \\G_{2}  \end{array}\right] =  \left[\begin{array}{ccc}102*10^{-5} \\97*10^{-5}  \end{array}\right]

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