The coordinate of a particle in meters is given by x(t) = 16t − 3.0t3, where the time t is in
1 answer:
Answer:
t = -4/3 s, t = 4/3 s
Explanation:
I am ASSUMING that you want to know the time(s) the particle is at rest.
and that your position equation is x(t) = 16t − 3.0t³
IF those assumptions are true
THEN
velocity is the derivative of position
v(t) = 16 - 9t²
the particle will be at rest when velocity is zero
0 = 16 - 9t²
9t² = 16
t² = 16/9
t = ± 4/3
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