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2 years ago

If you had 3.6 moles of AI(NO3)3, how many grams would you expect to have?

Chemistry

1 answer:

Ludmilka [50]2 years ago

4 0

766.7856 g

Molecular weight of Aluminium Nitrate is 212.996 g/mol. 3.6 moles of Aluminium Nitrate is: 212.996 × 3.6 = 766.7856

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drek231 [11]

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The ideal gas has been given as the gas where there has been negligible amount of interatomic collisions. The ideal gas equation has been given as:

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<h3>Computation for the moles of gas</h3>

The gi<em>ve</em>n gas has standard pressure, $P=1\rm atm$

The volume of the gas has been, $V= 0. 500 \;\rm L$

The temperature of the gas has been, $T=15^\circ \text C\\
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Substituting the values for the moles of gas, <em>n:</em>

<em />

<em /> $\rm 1\;\times\; 0. 500 =\textit n\;\times\;0.08214\;atm.L/mol.K\;\times\;288\;K\\\\
\textit n=\dfrac{0. 500}{0.08214\;\times\;288} \;mol\\\\
\textit n=0.021\;mol$

The moles of gas in the bottle has been 0.021 mol.

Learn more about ideal gas, here:
brainly.com/question/8711877

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