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iVinArrow [24]
3 years ago
11

What information does an equilibrium constant give about a reaction?

Chemistry
2 answers:
bogdanovich [222]3 years ago
6 0

Answer:

c

Explanation:

natima [27]3 years ago
3 0

Answer:

Answer is C

Explanation:

You might be interested in
Two molecules of one reactant combine with 3 molecules of another to produce 5 molecules of a product.
maksim [4K]

Answer:

A = 2A + 3B → 5C

Explanation:

The two molecule of A and three molecules of B will react to form the five molecules of C.

2A + 3B   →   5C

Other options are incorrect because,

B = A₂ + B₃  →   C₅

in this reaction one molecule of A₂ and one molecule of B₃ combine to form one molecule of C₅.

C = 2A + 5B   →  3C

in this reaction two molecules of A and five molecules of B combine to form three molecule of C.

D = A₂ + B₃  →  C₃

in this reaction one molecule of  A₂ and one molecule of B₃ combine to from one molecule of C₃.

3 0
3 years ago
Organic molecules always:
trapecia [35]
Organic chemistry is the study of molecules containing carbon, so A
8 0
4 years ago
If an oxygen has 1s2 2s2 2p4 , how many more electrons should it have to be octet .
Maru [420]

Answer:

14

Explanation:

8 0
3 years ago
How many grams of CH4 will be in a 500ml contain at STP?
ArbitrLikvidat [17]

Answer:

Mass = 0.32 g

Explanation:

Given data:

Mass of CH₄ = ?

Volume of CH₄ = 500 mL (500 mL× 1L/1000 mL= 0.5 L)

Temperature = 273 K

Pressure = 1 atm

Solution:

Volume of CH₄:

500 mL (500 mL× 1L/1000 mL= 0.5 L)

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

By putting values,

1 atm× 0.5 L = n×0.0821 atm.L/ mol.K  × 273 K

0.5 atm.L = n×22.4 atm.L/ mol

n = 0.5 atm.L / 22.4 atm.L/ mol

n = 0.02 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.02 mol × 16 g/mol

Mass = 0.32 g

7 0
3 years ago
2. I need to find the angle of corner of a room, what tool could I use?
Pavlova-9 [17]
If anything you would use a protractor but that’s not a answer.... so I would pick whatever relates to a protractor
6 0
4 years ago
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