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Serjik [45]
3 years ago
9

If the mirror moves at 1.5m/s towards Peter while Peter remains at rest, what will he observe? Explain your reasoning

Physics
1 answer:
Mashcka [7]3 years ago
7 0

Answer:

Peters image will grow bigger

Explanation:

In this situation, only Peter is at rest and the mirror is in motion at 1.5m/s heading towards Peter.

From afar, Peter will look small in the mirror that is his image will be small When the mirror is moved at 1.5m/s Peter being the observer will notice that his image grows bigger and bigger.

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At sunrise two old women started to walk towards each other. one started from point a and went towards point b while the other s
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Let the distance between points a and b = d

For the women starting from a her velocity be V_1 and for the women starting from b her velocity be V_2

Let the rising time of sun = x AM

We have  V_1 = \frac{d}{12+4-x}

and we also have  V_2 = \frac{d}{12+9-x}

At they meet means, they both travel a combined distance of d

So we have   V_1*(12-x)+V_2*(12-x)=d

Substituting velocity values we will get

  \frac{d}{12+4-x}*(12-x)+\frac{d}{12+9-x}*(12-x)=d\\ \\ \frac{12-x}{12+4-x}+\frac{12-x}{12+9-x}=1\\ \\ \frac{12-x}{16-x}+\frac{12-x}{21-x}=1\\ \\ 252-21x-12x+x^2+192-12x-16x+x^2=336-16x-21x+x^2\\ \\ x^2-24x+108=0\\ \\ (x-6)(x-18)=0\\ \\

 x= 6 AM or 18 AM, but 18 AM is not possible,

Sun rise time is 6 AM


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