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2 years ago

Which tool can be used to measure the volume of a liquid to one decimal place?

Physics

2 answers:

My name is Ann [436]2 years ago

9 0

Graduated cylinder bruh.

Gelneren [198K]2 years ago

4 0

Graduated cylinder is your answer

You might be interested in

Calculate the energy that 1.5 kg of mass contains

Vsevolod [243]

Answer:

$4.5(10)^8$ joules

Explanation:

Mass–energy equivalence is the principle that says that anything that has mass has an equivalent amount of energy. Converse is also true.

The relation between energy and mass is given by $E=mc^2$

Here, E denotes energy, m denotes mass and c denotes speed of light

Mass $(m)=1.5\,\,kg$

Speed of light (c) = 3 × $10^8$ m/s

Therefore,

$E=1.5(3)(10)^8=4.5(10)^8$ joules.

The S.I. unit of energy is joules which is equal to $1\,\,kg\,\,m^2/s^2$

4 0

2 years ago

An electron is trapped in an infinite square-well potential of width 0.6 nm. If the electron is initially in the n = 4 state, wh

grandymaker [24]

Answer:

E₁ = 1.042 eV

E₄₋₃= 7.29 eV

E₄₋₂= 12.50 eV

E₄₋₁= 15.63 eV

E₃₋₂= 5.21eV

E₃₋₁= 8.34eV

E₂₋₁= 3.13eV

Explanation:

The energy in an infinite square-well potential is giving by:

$E = \frac {h^{2} n^{2}}{8mL^{2}}$

<em>where, h: Planck constant = 6.62x10⁻³⁴J.s, n: is the energy state, m: mass of the electron and L: widht of the square-well potential </em>

<u>The energy of the electron in the ground state, </u><u>n = 1</u><u>, is: </u>

$E_{1} = \frac {(6.62 \cdot 10^{-34})^{2} (1)^{2}}{(8) (9.11 \cdot 10^{-31}) (0.6 \cdot 10^{-9} m)^{2}}$

$E_{1} = 1.67 \cdot 10^{-19} J = 1.042 eV$

The photon energies that are emitted as the electron jumps to the ground state is the difference between the states:

$E_{\Delta n} = \Delta n^{2} E_{1}$

$E_{(4 - 3)} = (4^{2} - 3^{2}) 1.042 eV = 7.29eV$

$E_{(4 - 2)} = (4^{2} - 2^{2}) 1.042 eV = 12.50eV$

$E_{(4 - 1)} = (4^{2} - 1^{2}) 1.042 eV = 15.63eV$

$E_{(3 - 2)} = (3^{2} - 2^{2}) 1.042 eV = 5.21eV$

$E_{(3 - 1)} = (3^{2} - 1^{2}) 1.042 eV = 8.34eV$

$E_{(2 - 1)} = (2^{2} - 1^{2}) 1.042 eV = 3.13eV$

Have a nice day!

7 0

2 years ago

An object with a mass of 7.60 kg is moving to the right and experiences an applied force of 50 N to the right. The friction forc

horrorfan [7]

Answer:

Explanation:

We will use the equation F - f = ma, which is a fancy way of stating Newton's 2nd Law.

F = +50.0,

f = -30.0,

m = 7.60 kg. Therefore:

50.0 - 30.0 = 7.60a and

20.0 = 7.60a and

a = 20.0/7.60 so

a = 2.63 m/s/s to the right

4 0

2 years ago

Can anyone help with this?

sleet_krkn [62]

Answer:

A. The volume of the object

Explanation:

First of all, it can only PROBABLY be A or D

But why is it only A?

Mass = The amount of matter in an object (nothing related here)
Volume = How much space is the object taking (super related here)

It's VOLUME here and not MASS here because:

It it would be Mass, then the object size could be anything, but the liquid wouldn't move as much higher.
But because it is Volume, it is taking space, which makes the liquid move
If the Mass would be the answer, then it would be totally not related, because mass isn't related over here, it matters about size.

<h2>Hence, A. The volume of the object </h2>

is your answer!!!!

4 0

1 year ago

Read 2 more answers

Hola me pueden ayudar con este problema de física....por favor mirar la imagen.. gracias

makkiz [27]

Si la velocidad es 3 m/s, y ellos quieren saber la distancia despues 2 segundos, necesita que multiplicar 2 y 3.

La respeusta debiera ser 6m.

8 0

2 years ago