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jenyasd209 [6]
3 years ago
5

Which tool can be used to measure the volume of a liquid to one decimal place?

Physics
2 answers:
My name is Ann [436]3 years ago
9 0
Graduated cylinder bruh. 
Gelneren [198K]3 years ago
4 0
Graduated cylinder is your answer

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A horizontal force of 100 N is used to pull a crate, which weighs 500 N, at constant velocity across a horizontal floor. What is
Ilya [14]

Answer:

0.2

Explanation:

Horizontal force=100N

Weight of crate=500 N

We have to find the coefficient of kinetic friction.

Normal ,N=Weight=500N

Horizontal force,F_x=\mu_kN

Where F_x=Horizontal force

N=Normal force

\mu_k=Coefficient of kinetic friction

Substitute the values in the formula

100=\mu_k(500)

\mu_k=\frac{100}{500}=0.2

Hence, the coefficient of kinetic friction =0.2

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Assume you are riding in a plane that is moving at a speed of 600kmh relative to the ground. If you walk from the back to the fr
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What is the unit of mu (m) in the equation of Ffriction=miu F formal explan<br>​
erica [24]

Both F's are forces, so µ must be unitless/dimensionless.

F[friction] = µ F[normal]

Or, more explicitly in terms of the units:

(Newtons) = (constant) (Newtons)

8 0
2 years ago
A copper rod 0.570 � long and with a mass 0.05900 �� is suspended from two thin wire. At right angle to the rod is a uniform mag
finlep [7]

Answer:

a) Left to right

b) 1.51 A

Explanation:

a)

The gravitational force on the rod due to its mass is in downward direction. hence to levitate the rod, the magnetic force on the rod must be in upward direction.

The magnetic field is inward to page and magnetic force must be upward. Using right hand rule, the current must be flowing from left to right.

Left to right

b)

L = length of the copper rod = 0.570 m

m = mass of the rod = 0.059 kg

B = magnitude of magnetic field in the region = 0.670 T

θ = Angle between the magnetic field and rod = 90

i = current flowing throw the rod = ?

The magnetic force on the rod balances the gravitational force on the rod. hence

Magnetic force = gravitational force

mg = i B L Sinθ

(0.059) (9.8) = i (0.670) (0.570) Sin90

i = 1.51 A

6 0
3 years ago
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