The initial velocity of go-kart is 2.5 m/s.
<u>Explanation:</u>
Here, the uniform acceleration of go-kart is given as 0.5 m/s². Also the time required by it to stop is also given as 5 s. As acceleration is the measure of change in velocity per unit time.
In this case, the velocity should be changed from a value to zero to come to rest. So the initial velocity will be positive value and final velocity is zero.
As we know the values of acceleration, final velocity and time, the initial velocity can be easily determined as follows.
Since, final velocity is zero, acceleration is 0.5 m/s² and time is 5 s, then,
Initial velocity = 0.5 × 5 = 2.5 m/s.
So the initial velocity of go-kart is 2.5 m/s.
Answer:
Explanation:
Let consider the observer as an inertial reference frame. The object is modelled after the Principle of Momentum Conservation:
The speed of the more massive piece is:
The kinetic energy added to the system is:
![\Delta K = \frac{1}{2}\cdot [(5.333\,kg)\cdot (0\,\frac{m}{s} )^{2}+(26.665\,kg )\cdot (31.202\,\frac{m}{s} )^{2}]-\frac{1}{2}\cdot (32\,kg)\cdot (26\,\frac{m}{s} )^{2}](https://tex.z-dn.net/?f=%5CDelta%20K%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%5B%285.333%5C%2Ckg%29%5Ccdot%20%280%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D%2B%2826.665%5C%2Ckg%20%29%5Ccdot%20%2831.202%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D%5D-%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%2832%5C%2Ckg%29%5Ccdot%20%2826%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D)
Answer:
Explanation:
Its the 2nd one on the left (the bolded one)
If the ice absorbed 350,000 joules in 5 minutes, then it absorbed energy
at the rate of
(350,000 joules) / (5 x 60 seconds) =<em> 1,166-2/3 watts</em> .
Surely the ice cube didn't absorb every joule delivered to the cooking chamber,
so the microwave oven's cooking power had to be significantly more than that.
The acceleration due to gravity near the surface of the planet is 27.38 m/s².
<h3>
Acceleration due to gravity near the surface of the planet</h3>
g = GM/R²
where;
- G is universal gravitation constant
- M is mass of the planet
- R is radius of the planet
- g is acceleration due to gravity = ?
g = (6.626 x 10⁻¹¹ x 2.81 x 5.97 x 10²⁴) / (6371 x 10³)²
g = 27.38 m/s²
Thus, the acceleration due to gravity near the surface of the planet is 27.38 m/s².
Learn more about acceleration due to gravity here: brainly.com/question/88039
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