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emmainna [20.7K]
2 years ago
10

When an object radiates heat, the strength of this radiation far from the object decreases when distance from the source increas

es as shown in the graph below:
That is, radiated heat is much stronger near its source.

The universe is full of heat that was radiated by a source that no longer exists. This heat is known as cosmic background radiation. Cosmic background radiation is not stronger in any one direction or part of the universe than in others.

The following image is a map of the cosmic background radiation. Red areas are only 0.0002 K hotter than the blue areas. The overall temperature of the radiation is 2.725 K.


Image by the WMAP team, courtesy of the Legacy Archive
for Microwave Background Data Analysis (LAMBDA) supported by NASA

What does the uniformity of this radiation imply about its source?
A.
The source of cosmic background radiation existed for a very long time.
B.
The source of cosmic background radiation existed for a very short time.
C.
The source of cosmic background radiation moved randomly.
D.
The source of cosmic background radiation filled the entire universe.
Physics
2 answers:
jenyasd209 [6]2 years ago
5 0
Sooooooooooo I’m pretty sure the answer is b
rodikova [14]2 years ago
4 0

Answer:

B I am not sure about the answer but it may be B

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velikii [3]

Answer:

Yes

Explanation:

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F = Gm1m2/r²

This is a general physical law derived from

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when distance is doubled the gravitational force will be reduced by quarter not half.

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3 years ago
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Evidence suggests that there may be _______ momentum and ________ reversal patterns in stock price behavior.
bearhunter [10]

CORRECT ANSWER:

D. short-run; long run

STEP-BY-STEP EXPLANATION:

The whole question from book is

Evidence suggests that there may be _______ momentum and ________ reversal patterns in stock price behavior.

A. short-run; short-run

B. long-run; long-run

C. long-run; short-run

D. short-run; long run

Evidence suggests that there may be <em><u>short-run</u></em> momentum and <em><u>long run </u></em>reversal patterns in stock price behavior.

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3 years ago
Wha is the movement of the balloon when brought near to the can after removing your hand?​
DIA [1.3K]

Answer:

the answer is static electricity

3 0
3 years ago
Consider a Carnot heat-engine cycle executed in a closed system using 0.025 kg of steam as the working fluid. It is known that t
ArbitrLikvidat [17]

Answer:

The temperature of the steam during the heat rejection process is 42.5°C

Explanation:

Given the data in the question;

the maximum temperature T_H in the cycle is twice the minimum absolute temperature T_L in the cycle

T_H  = 0.5T_L

now, we find the efficiency of the Carnot cycle engine

η_{th = 1 - T_L/T_H

η_{th = 1 - T_L/0.5T_L

η_{th = 0.5

the efficiency of the Carnot heat engine can be expressed as;

η_{th = 1 - W_{net/Q_H

where W_{net is net work done, Q_H is is the heat supplied

we substitute

0.5 = 60 / Q_H

Q_H = 60 / 0.5

Q_H = 120 kJ

Now, we apply the first law of thermodynamics to the system

W_{net = Q_H - Q_L

60 = 120 -  Q_L

Q_L = 60 kJ

now, the amount of heat rejection per kg of steam is;

q_L = Q_L/m

we substitute

q_L = 60/0.025

q_L = 2400 kJ/kg

which means for 1 kilogram of conversion of saturated vapor to saturated liquid , it takes 2400 kJ/kg of heat ( enthalpy of vaporization)

q_L = h_{fg = 2400 kJ/kg

now, at  h_{fg  = 2400 kJ/kg from saturated water tables;

T_L = 40 + ( 45 - 40 ) ( \frac{2400-2406.0}{2394.0-2406.0}\\} )

T_L = 40 + (5) × (0.5)

T_L = 40 + 2.5

T_L = 42.5°C  

Therefore, The temperature of the steam during the heat rejection process is 42.5°C  

4 0
3 years ago
The combustion of propane (C3H8) in the presence of excess oxygen yields CO2 and H2O: C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g) W
zimovet [89]

Answer:

1.2

Explanation:

2.0 mol O₂ × (3 mol CO₂ / 5 mol O₂) = 1.2 mol CO₂

4 0
3 years ago
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