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KATRIN_1 [288]
3 years ago
12

What is y=mx+b explain

Engineering
2 answers:
N76 [4]3 years ago
6 0
Someone already answered but don’t tap on any links
elena-s [515]3 years ago
5 0

Answer:

Explanation:

The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.

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An aggregate blend is composed of 65% coarse aggregate by weight (Sp. Cr. 2.635), 36% fine aggregate (Sp. Gr. 2.710), and 5% fil
den301095 [7]

Answer:

Explanation:

From the given information:

Addition of all the materials = 65+ 36+ 5 +6 = 112  which is higher than 100 percentage; SO we need to find;

The actual percentage of each material which can be determined as follows:

Percentage of the coarse aggregate will be = 65 × 112/100

= 72.80%

Percentage of the Fine aggregate will be = 36 × 112/100

= 40.32%

Percentage of the filler  will be = 5 × 112/100

= 5.6%

Percentage of the   asphalt binder will be = 6 × 112/100

= 6.72 %

So; the theoretical specific gravity (Gt) of the mixture can be calculated as follows:

Gt = 100/( 72.80/2.635 + 40.32/2.710 + 5.6/2.748 + 6.72/1.088)

Gt = 100/( 27.628 + 14.878 + 2.039 + 6.177)

Gt = 100/ (50.722)

Gt =1.972

Also;Given that the bulk density = 143.9 lb/ft³

LIke-wsie ; as we know that unit weight of water is =62.43lb/cu.ft

Hence, the bulk specific gravity of the mix (Gm) = 143.9/62.43

=2.305

The percentage of air  void  = (Gt -Gm )× 100/ Gt

= (1.972 - 2.305) ×  100/ 1.972

= -16.89%

The percentage of the asphalt binder is =(6.72/1.088*100)/(72.80+40.32+5.6+6.72)/2.305)

= 617.647/54.42

= 11.35%

Thus; the percentage voids in mineral aggregate =  -16.89% + 11.35%

the percentage voids in mineral aggregate = -5.45%

The percent voids filled with asphalt. = 100 × 11.35/-5.45

The percent voids filled with asphalt = - 208.26 %

7 0
3 years ago
20. It is important to keep a copy of your written plan and safety records off-site.
Verdich [7]

Answer:

A

Explanation:

Incase you need to re-read or you need to refresh your memory.

Also, Incase something happens, you will have the rules and guidelines.

4 0
3 years ago
Quadrilateral ABCD is a rectangle.<br> If m ZADB = 7k + 60 and mZCDB = -5k + 40, find mZCBD.
yuradex [85]

Hope this helps...........

8 0
3 years ago
A closed, 0.4-m-diameter cylindrical tank is completely filled with oil (SG 0.9)and rotates about its vertical longitudinal axis
egoroff_w [7]

Answer: p_{B} - p_{A} = 28800 Pa or 28.8 kPa

Explanation: To determine the pressure of a liquid in a rotating tank,it is used:

p = \frac{p_{fluid}.w^{2}.r^{2} }{2} - γfluid . z + c

where:

p_{fluid} is the liquid's density

w is the angular velocity

r is the radius

γfluid.z is the pressure variation due to centrifugal force.

For this question, the difference between a point on the circumference and a point on the axis will be:

p_{B} - p_{A} = \frac{p_{fluid}.w^{2}.r_{B} ^{2} }{2} - γfluid.z_{B} - (\frac{p_{fluid}.w^{2}.r_{A} ^{2} }{2} - γfluid.z_{A})

p_{B} - p_{A} = \frac{p_{fluid}.w^{2}}{2} (r_B^{2} - r_A^{2} ) - γfluid(z_{B} -z_{A})

Since there is no variation in the z-axis, z = 0 and that the density of oil is 0.9.10³kg/m³:

p_{B} - p_{A} = \frac{p_{fluid}.w^{2}}{2} (r_B^{2} - r_A^{2} )

p_{B} - p_{A} = \frac{0.9.10^3.40^2}{2}(0.2^2 - 0)

p_{B} - p_{A} = 28800

The difference in pressure between two points, one on the circumference and the other on the axis is p_{B} - p_{A} = 28800 Pa or 28.8 kPa

8 0
3 years ago
Create a series of eight successive displacements that would program a robot to move in an octagonal path that is as close as yo
Komok [63]

Answer:

bts biot bts biot jungkukkk

jungkukkkbiot

Explanation:

bts biot bts biot jungkukkk

jungkukkkbiot

5 0
3 years ago
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