Answer:
Molar concentration is 0.050 M
Explanation:
Osmotic pressure -
Osmotic pressure is pressure applied to stop the flow of solvent across a semipermeable membrane, from its high concentration to its low concentration , it is a type of colligative property , i.e. , it depends on the number of moles of solute.
Osmotic pressure can be calculated from the formula -
π = CRT
π = Osmotic pressure ( in atm )
C = molarity of the solution
R = universal gas constant ( 0.082 L.atm / K.mol )
T = temperature ( Kelvin )
From the question ,
π = 945 torr
since,
760 torr = 1 atm
1 torr = 1 / 760 atm
945 torr = 1 / 760 * 945 atm
945 torr = 1.24 atm
Temperature = T = 28°C
(adding 273 To °C to convert it to K)
T = 28 + 273 = 301 K
Using the equation of osmotic pressure,
π = CRT
C = π / RT
putting the
C = 1.24 atm / 0.082 L.atm / K.mol * 301 K
C = 1.24 / 24.68
C = 0.050 M
Hence,
The Molar concentration is 0.050 M.
First we must write a balanced chemical equation for this reaction
The mole ratio for the reaction between 
and 
is 1:2. This means 1 moles of will neutralize 2 moles . Now we find the moles of each reactant based on the mass and molar mass.
The was enough to neutralize the acid because 18.87:39.67 is the same as 1:2 mol ratio.
Consider the following equation:0.0136 g + 2.70 × 10-4 g - 4.21 × 10-3 g = ? How many digits to the right of the decimal point should be used to report the result? =2, Choose the correct answer=9.66 × 10^-3 g, Which metric unit would be the best choice to report the result?=mg
The atomic number of an atom is determined by the number of protons it has..
It is also the whole number shown on the periodic table
Answer is: the molar mass od sodium carbonate (Na₂CO₃) is 106.0 g/mol.
M(Na₂CO₃) = 2 · Ar(Na) + Ar(C) + 3 · Ar(O).
M(Na₂CO₃) = 2 · 23 + 12 + 3 · 16 · g/mol.
M(Na₂CO₃) = 46 + 12 + 48 · g/mol.
M(Na₂CO₃) = 106 g/mol; molar mass of sodium carbonate.
Ar is relative atomic mass (the ratio of the average mass of atoms of a chemical element to one unified atomic mass unit) of an element.
