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Arturiano [62]
3 years ago
12

When you know both the speed and direction of an object’s motion, you know the

Physics
1 answer:
VladimirAG [237]3 years ago
3 0

Answer:

When you know both the speed and direction of an object's motion, you know the velocity of the object.

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A tomato of mass 0.18 kg is dropped from a tall bridge. If the tomato has a speed of 11 m/s just before it hits the ground, what
kondor19780726 [428]
The kinetic energy of the tomato is : 

K.E =  1/2 mv^2

K.E = 1/2 x 0.18 kg x 11 m/S^2

K.E = 0.99

Hope this helps
7 0
3 years ago
Find the potential energy associated with a 61-kg hiker atop New Hampshire's Mount Washington, 1900 m above sea level. Take the
Natali [406]

Answer:

The potential energy of the hiker is 1.13\times 10^6\ J.

Explanation:

Given that,

Mass of the hiker, m = 61 kg

Height above sea level, h = 1900 m

We need to find the potential energy associated with a 61-kg hiker atop New Hampshire's Mount Washington. The potential energy is given by :

E=mgh

g is the acceleration due to gravity

E=61\ kg\times 9.8\ m/s^2\times 1900\ m\\\\E=1.13\times 10^6\ J

So, the potential energy of the hiker is 1.13\times 10^6\ J. Hence, this is the required solution.

8 0
3 years ago
If 3.61 m3 of a gas initially at STP is placed under a pressure of 2.67 atm , the temperature of the gas rises to 37.9 ∘C. What
Pavel [41]

Answer: 1.54m^3

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas at STP = 1 atm

P_2 = final pressure of gas = 2.67 atm

V_1 = initial volume of gas = 3.61m^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas at STP = 0^oC=273+0=273K

T_2 = final temperature of gas = 37.9^oC=273+37.9=310.9K

Now put all the given values in the above equation, we get:

\frac{1atm\times 3.61m^3}{273K}=\frac{2.67\times V_2}{310.9K}

V_2=1.54m^3

Thus the final volume will be 1.54m^3

7 0
3 years ago
To celebrate a victory, a pitcher throws her glove straight upward with an initial speed of 5.3 m/s. How long does it take for t
Elena-2011 [213]

Hello!!

For the maximum height the final velocity is zero, <u>because can't up more.</u>

Then, use the formula:

V = Vi + gt

Replacing, we have:

0 m/s = 5,3 m/s + (-9,8 m/s² * t)

0 m/s - 5,3 m/s = -9,8 m/s² * t

(-5,3 m/s) / -9,8 m/s² = t

t = 0,54 s

The time it will take to reach the maximum height is <u>0,54 seconds.</u>

3 0
2 years ago
A 0.660 kg ball is dropped from rest from the top of a building and falls for 5.65 seconds. How tall was the building ?
kirill115 [55]

Answer:

The height of the building is approximately 156.58 m

Explanation:

The mass of the ball dropped from rest from the building top = 0.660 kg

The time in which the ball falls, t = 5.65 seconds

The height, h, of the building is given from the following equation of motion;

h = u·t + ¹/₂·g·t²

Where;

u = The initial velocity of the ball = 0 m/s

g = The acceleration due to gravity = 9.81 m/s²

Plugging in the values, we have;

h = 0 × 5.65 + ¹/₂ × 9.81 × 5.65² ≈ 156.58 m

The height of the building, h ≈ 156.58 m.

6 0
3 years ago
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