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yan [13]
3 years ago
7

To celebrate a victory, a pitcher throws her glove straight upward with an initial speed of 5.3 m/s. How long does it take for t

he glove to reach its maximum height
Physics
1 answer:
Elena-2011 [213]3 years ago
3 0

Hello!!

For the maximum height the final velocity is zero, <u>because can't up more.</u>

Then, use the formula:

V = Vi + gt

Replacing, we have:

0 m/s = 5,3 m/s + (-9,8 m/s² * t)

0 m/s - 5,3 m/s = -9,8 m/s² * t

(-5,3 m/s) / -9,8 m/s² = t

t = 0,54 s

The time it will take to reach the maximum height is <u>0,54 seconds.</u>

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Orlov [11]

Answer:

0.0172rad/day=1.99x10^{-7}rad/second

Explanation:

The definition of angular velocity is as follows:

\omega=2\pi f

where \omega is the angular velocity, and f is the frequency.

Frequency can also be represented as:

f=\frac{1}{T}

where T is the period, (the time it takes to conclude a cycle)

with this, the angular velocity is:

\omega=\frac{2\pi}{T}

The period T of rotation around the sun 365 days, thus, the angular velocity:

\omega=\frac{2\pi}{365days}=0.0172rad/day

if we want the angular velocity in rad/second, we need to convert the 365 days to seconds:

Firt conveting to hous

365days(\frac{24hours}{1day} )=8760hours

then to minutes

8760hours(\frac{60minutes}{1hour} )=525,600minutes

and finally to seconds

525,600minutes(\frac{60seconds}{1minute})=31,536x10^3seconds

thus, angular velocity in rad/second is:

\omega=\frac{2\pi}{31,536x10^3seconds}=1.99x10^{-7}rad/second

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3 years ago
What constant acceleration is required to increase the speed of a car from 26 mi/h to 51 mi/h in 5 seconds
mr_godi [17]

2.25 m/s² of acceleration is required to increase the speed of a car from 26 mi/h to 51 mi/h in 5 seconds.

To find the answer, we need to know about the acceleration.

<h3>What is acceleration?</h3>
  • Acceleration is given as the ratio of velocity to time.
  • Mathematically, acceleration= velocity/time.
<h3>What is the acceleration required to increase the speed of a car from 26 mi/h to 51 mi/h in 5 seconds?</h3>
  • Here change in velocity of the car is 51-26= 25 mi/h.
  • As 1 mi/h = 0.45 m/s. So 25mi/h = 11.25 m/s.
  • Acceleration= (11.25m/s)/5s = 2.25 m/s².

Thus, we can conclude that the constant acceleration is 2.25 m/s².

Learn more about the acceleration here:

brainly.com/question/460763

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2 years ago
Mike enters a revolving door that is not moving. explain where and how mike should push to produce a torque with the least amoun
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Mike enters a revolving door that is not moving. Mike should push at the edge of the door where it is largest distance from the pivot point in order to produce a torque with the least amount of force. Torque is equal to t = force x distance.

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One has to carry out some research in order to know what went wrong and should also validate the hypothesis by consulting with ones peers. By doing this, the most likely causes of the issues will be gotten.

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